When x → + ∞, which of the following is infinitesimal: ln (1 + x), SiNx / x, X ^ 2 / x + 1, e ^ (- 1 / X ^ 2)
sinx/x
RELATED INFORMATIONS
- 1. 4. When x → + ∞, an infinite number of the following variables is a.b.ln (1 + x) c.sinx d.e-x
- 2. When X - >, the following infinitesimal equivalent to X is? A 3x B SiNx C ln (1 + x ^ 2) d x + SiNx
- 3. When x → 0, which of the following functions is not the equivalent infinitesimal of arctanx
- 4. When x approaches 0, A.E ^ x b.sin 1 / (1 + x) c.ln (2 + x) is infinitesimal When x approaches zero, the following variables are infinitesimal A.e^x B.sin 1/(1+x) C.ln(2+x) D.1-cosx
- 5. When 3 π
- 6. Infinitesimal equivalence problem: X → 0, the following infinitesimal equivalent to e ^ 2x-1 is: A. x B. 2x C. 4x D. x ^ 2 seeking process
- 7. Find the equivalent infinitesimal of (1 + 2x) ^ 1 / 2 - (1 + 3x) ^ 1 / 3 (x - > 0) Expressed as a power function of X
- 8. How to calculate the limit of LIM (x - > 0) (1-2 / x + 2)
- 9. LIM (x tends to 3) 3 / (x ^ 2-6x + 9)
- 10. Let LIM (x approach to 0) (e ^ X - (x ^ 2 + ax + b)) / X be equal to 2, and find the value of a and B
- 11. limx→0(x^3+1)/(x+1)sin2x
- 12. What is the limit of sin2x / x?
- 13. Let f (x) have a function of second order, and f '' (x) > 0, limx tends to 0f (x) / x = 1. It is proved that when x > 0, f (x) > X
- 14. If f '(0) = 1, then limx → 0f (x) - f (- x) / X=
- 15. Let f (x) be differentiable at x = 0 and f (0) = 0, then limx tends to 0, f (x) / x =?
- 16. Is E2x power + 1 equivalent infinitesimal 2x or 2x + 2
- 17. When x approaches 0, what order of infinitesimal is x ^ 2-sinx!
- 18. What order of infinitesimal and high number is X-1
- 19. What is the value of (2sinx-sin2x) / (x-sinx)? When I solve the problem, I first seek the derivative of the numerator denominator, the denominator is 1-cosx, and the numerator is 2cosx-2cos2x? Then I think if X -- > 0, the denominator is equal to 1, and the numerator is equal to 0, is this the answer? But if we expand cos2x into 2cos ^ 2x-1, the numerator is equal to 2. Strange, we can't expand it casually
- 20. X → 0, f (x) = x-sinx is the infinitesimal of higher order g (x) = xsinx We hope to divide f (x) and G (x) to get the form of the ratio of two infinitesimals, that is, the type of 0:0, and then judge their infinitesimal relationship from the simplified result, which may involve the equivalent infinitesimal transformation