A circle passes through a (- 2,1), B (5,0) and the center of the circle is on the straight line x-3y-10 = 0 A circle passes through a (- 2,1), B (5,0) and the center of the circle is on the straight line x-3y-10 = 0

The midpoint of a (- 2,1), B (5,0) is (3 / 2,1 / 2)
Kab=-1/7
The vertical of AB is l: y = 7x-10
And x-3y = 10, we get x = 1, y = - 3
So r = 5
The equation of circle is (x-1) ^ 2 + (y + 3) ^ 2 = 25

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