2/1*4+2/4*7+2/7*10+2/10*13+.+2/(3n-2)(3n+1)

2/1*4+2/4*7+2/7*10+2/10*13+.+2/(3n-2)(3n+1)

2/(3n-2)(3n+1)=(2/3)*[1/(3n-2)-1/(3n+1)]
So the original formula = (2 / 3) * [1-1 / 4 + 1 / 4-1 / 7 + 1 / 7-1 / 10 + 1 / 10-1 / 13 +. + 1 / (3n-2) - 1 / (3N + 1)]
=(2/3)*[1-1/(3n+2)]
=(6n+2)/(9n+6)