Sn/Tn=3n+1/2n-1 RT please as soon as possible! Thank you~ If the sum of their first n terms is Sn / TN = 3N + 1 / 2N-1, then the ratio of the fifth term of these two sequences is? I forgot to enter the title when I was excited~

Let an first term be A1, tolerance be D1, BN first term be B1, tolerance be d2sn / TN = [Na1 + n (n-1) / 2D1] / [NB1 + n (n-1) / 2d2] when n = 9, S9 / T9 = (3 * 9 + 1) / (2 * 9-1) = 28 / 17 = [9a1 + 9 (9-1) / 2D1] / [9b1 + 9 (9-1) / 2d2] = (9a1 + 36d1) / (9b1 + 36d2) = (a1 + 4d1) / (B1 + 4D2)

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