The intersection of a and B is B. can a and B be empty
Yes, an empty set is also a set, which can't be ignored
RELATED INFORMATIONS
- 1. If the intersection of a and B is an empty set, then at least one of a and B is an empty set?
- 2. Is the intersection of a and a empty
- 3. Does the intersection of a and B equal a mean that B equals a
- 4. What does it mean that the intersection of a and B equals the union of a and B?
- 5. A ∪ B = a, then a can be equal to B, the intersection of a and B is equal to B, can a be equal to B
- 6. If a intersection B equals B, is a equal to B? That is, the intersection of a and B is equal to B. does it mean that set a and B are equal
- 7. What is the intersection of an empty set and a? 1. What is the intersection of an empty set and a (non empty set)? 2. Why {x | x > 2} {x | X2, or x
- 8. The intersection of a and B consists of all elements belonging to a and B For "a ∩ B = {x | x ∈ a, and X belongs to B}, we can not only think that any element of a ∩ B is the common element of a and B, but also that the common elements of a and B belong to a ∩ B, which is the meaning of" all "in the text definition, not" part "of the common element, Be clear and easy to understand, When the common elements of a and B are not in a ∩ B? What do you say···
- 9. If a = {x is greater than or equal to - 3 and less than 1} B = {x is greater than or equal to A-1 and less than or equal to a} and the intersection of a and B is not an empty set, then the value range of a
- 10. Given the complete set L = {x | x ∈ r}, set a = {x, X less than or equal to 1 or X ≥ 3}, set B = {x, K < x < K + 1, K ∈ r} and (C1a) ∩ B = empty set, then the value range of real number k is
- 11. Can the intersection of set a and set B be empty? Can it be set a or set B?
- 12. Let u = n, a = {x | x = 2K, K ∈ n}, B = {x | x = 2K + 1. K ∈ n}, find CUA, cub
- 13. Let u = Z, a = {x | x + 2K, K ∈ Z}, B = {x | x = 2K + 1, K ∈ Z}, find CUA, cub
- 14. When u = Z, a =, B = find CUA, cub
- 15. Let u = Z, a = {x | x = 2K, K ∈ Z}; b = {x | x = 2K + 1, K ∈ Z} find CUA, Cub? Let u = Z, a = {x | x = 2K, K ∈ Z}; b = {x | x = 2K + 1, K ∈ Z} find CUA, Cub? It's urgent
- 16. Let a = {x x = 2k-1, K ∈ Z}, B = {x x = 2K, K ∈ Z}, find a ∩ B, find a ∪ B
- 17. Let u = Z, a = {x = 2K, K ∈ Z}, B = {x | x = 2K + 1, K ∈ Z} CUA, Cub? Write the steps?
- 18. It is known that two points a and B are on the straight line y = X-1, and the difference between the abscissa of a and B is the root sign 2 Be as detailed as possible
- 19. If a + B = 4 radical a + 2 radical B-5, then a + 2B= The faster the better, small points do not become respect!
- 20. (√3+√2)^-1+ √(-2)+3 √-8 The number of positive solutions of inequality 2x-1 < 3 is If x < m + 1 If x > 2m-1, the value range of M is