Given 4x ^ 2 + 4x + 3 = y ^ 2 + 4Y. Find the value of X-Y

Given 4x ^ 2 + 4x + 3 = y ^ 2 + 4Y. Find the value of X-Y

There's something wrong with the title. It should be - in front of 3, otherwise I can't do it
4x²+4x-3=y²+4y
4x²+4x+1-y²-4y-4=0
(2x+1)²-(y+2)²=0
The square term is constant and nonnegative, the sum of the two square terms = 0, and both square terms = 0
2x+1=0 x=-1/2
y+2=0 y=-2
x-y=-(1/2)-(-2)=3/2
If the title is like this, then the title must be wrong, 3 should be preceded by - sign