It is known that the function f (x) = 1 + √ (2x-3) has an inverse function, and the point m (a, b) is not only on f (x) but also on the inverse function f (x)
X > = 3 / 2;
f(x)=1+√(2x-3)------------1;
F (x) = [(x-1) * (x-1) + 3] / 2-2; (on y = x symmetry)
The solution is x = 2, y = 2
Or x = 1 + √ (2x-3)
It can also solve x = 2, y = 2
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