1. A copper ball with a mass of 178 grams and a volume of 30 cubic centimeters is solid or hollow. What is the hollow volume? If the hollow part is filled with aluminum, what is the total mass? 2. In order to reduce the weight of the aircraft, an engineer changed a steel part into an aluminum part to reduce its mass by 1.56 kg. What is the mass of aluminum required? The density of steel is 7.9 × 10 cubic kg / cubic cm, and the density of aluminum is 2.7 × 10 cubic kg / cubic cm

1. A copper ball with a mass of 178 grams and a volume of 30 cubic centimeters is solid or hollow. What is the hollow volume? If the hollow part is filled with aluminum, what is the total mass? 2. In order to reduce the weight of the aircraft, an engineer changed a steel part into an aluminum part to reduce its mass by 1.56 kg. What is the mass of aluminum required? The density of steel is 7.9 × 10 cubic kg / cubic cm, and the density of aluminum is 2.7 × 10 cubic kg / cubic cm

1. P copper ball = m / v = 178g / 30cm3 = 5.9g/cm3 5.9g/cm3 < 8.9g/cm3 hollow
First calculate the volume of copper in the copper ball, v = m / P = 178g / 8.9g/cm3 = 20cm3
Hollow volume = V aluminum = 30cm3-20cm3 = 10cm3
M = PV = 10cm3 * 2.7g/cm3 = 27g m total = 27g + 178g = 205g
2. Mass reduced by 1.56kg
Equivalency relation P iron V-P aluminum v = 1.56 (making the same part V is equal ~ this is the implied condition)
V=0.0003
M al = PV = 2700 * 0.0003 = 0.81