If the square of a + 1 + (b-2) 2 = 0, find the square of (a + b) 2011 + the square of A2010
If the square of a + 1 + (b-2) 2 = 0
Then a + 1 = 0, B-2 = 0
The solution is a = - 1, B = 2
So (a + b) the square of 2011 + the square of A2010
=(-1+2)^2011+(-1)^2010
=1-1
=0
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