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In a certain electric field, the potential of point a is 100V, the charge q = 2 times 10 to the negative 9th power C, moves from point a to point B, and overcomes the electric field force to do work of 2 In an electric field, the potential of point a is 100V. If the charge q = 2 times 10 to the negative 9th power C is moved from point a to point B, and the work done by overcoming the electric field force is 2 times 10 to the negative 8th power J, what is the potential of point B?
WAB=EPA-EPB=qφA-qφB
φB=(qφA-WAB)/q=φA-WAB/q=100-(-2*10^-8)/2*10^-9=100+10=110v
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