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If a.b.c.d is an unequal integer and ABCD = 9, find the value of a + B + C + D Mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
The result is 0
It must be 2 positive and 2 negative in ABCD
We know that 1 times any number is constant (except 0)
So let a = 1, B = - 1
ab=-1
The root of 9 is 3
Let C = 3, d = - 3
cd=-9
Then: ABCD = - 1 × (- 9)
=9
a＋b＋c＋d=0
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