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Seek the master to solve the mathematics problem of the second grade of junior high school Xiao Li bought a kilogram of nugan watermelon in the market at the price of 0.8 yuan per kilogram and sold it in the market. After selling some of the watermelons, all the watermelons were sold out at a price of 0.4 yuan. The relationship between the sales and the kilogram of melons is shown in the figure. Xiao Li just got the solution on QQ and bought a total of 50kg watermelons. The first 40kg sold for 1.6 yuan, and the last 10kg sold for 1.2 yuan The revenue is 76-64 = 12 / 1.2 = 10, that is, 10kg, which is mainly not shown on Baidu 40 + 10 = 50kg 0.8*40+0.4*10 36 yuan
Xiao Li bought several kilos of watermelon from the wholesale market at the price of 0.8 yuan per kilogram for sale. After selling part of the watermelon, the rest of the watermelon was sold out at a price of 0.5 yuan per kilogram. The relationship between the sales amount and the kilogram of melon is shown in the figure, so Xiao Li earned (60 /...)
RELATED INFORMATIONS
- 1. It is known that A-B = 2, (A-1) (b-2) < ab (1) Find the value range of A; (2) If a & sup2; + 2Ab + A + B & sup2; - B = 38, find the value of a + B Clear steps are required
- 2. Boss Li, a fruit seller, sells a kind of high-grade fruit. If he makes a profit of 10 yuan per kilogram, he can sell 500 kg per day. According to the market survey, if the price of the imported fruit remains unchanged, if the price of the imported fruit increases by 1 yuan per kilogram, the daily sales volume will decrease by 20 kg. Now boss Li wants to make a profit of 6000 yuan per day and at the same time make the customers get benefits. How much yuan should the price of the fruit increase per kilogram I know the equation is (10 + x) x (500-20x) = 6000 But can you give me a detailed analysis, why do you want to do this, what does 10 + X Stand for What does 500-20x stand for What does 20x stand for? Why multiply 20kg by the price increase
- 3. There is a large oil tank in an oil depot. In the first 8 minutes, only the oil inlet pipe is opened but not the oil outlet pipe. When the oil in the oil tank reaches 24 tons (there is no oil in the crude oil tank), the oil inlet pipe and the oil outlet pipe are opened simultaneously for 16 minutes. The oil in the oil tank increases from 24 tons to 40 tons. Then the oil inlet pipe is closed and only the oil outlet pipe is opened until all the oil is discharged, It is assumed that the flow rates of the inlet pipe and the outlet pipe remain constant respectively in unit time Write the functional relationship between the oil storage quantity Q (ton) and the time t (minute) of oil in and out in this period
- 4. Exercises in volume two of junior high school mathematics The electric maintenance workers of the power supply bureau had to go to the suburb of 30 kilometers for electric maintenance. The maintenance workers left first by motorcycle. After 15 minutes, the repair car loaded with the required materials set out. As a result, they arrived at the same time. The speed of the repair car was 1.5 times that of the motorcycle. The speed of two kinds of cars was calculated 2. The total length of the expressway between a and B is 200 kilometers, which is 20 kilometers less than the original national highway. After the expressway was opened to traffic, the driving speed of a long-distance bus was increased by 45 kilometers per hour, and the driving time from a to B was shortened by half. The speed of the long-distance bus on the original national highway was calculated
- 5. Exercise 2 on page 54 of mathematics volume 2 of junior high school
- 6. Exercises of equations in the second volume of junior high school mathematics
- 7. Given that the mean of a sample m, 4,2,5,3 is n, and M + n = 4, then the variance of the sample is () solve equations 1 + 2 of X + 1 = 2x + 2 of X
- 8. What are the square root and the square root of the second power arithmetic of (- 4 / 13) The fourth power of minus thirteen Arithmetic square root square root
- 9. As shown in the figure, in rectangular ABCD, AC and BD intersect at point O, AE bisects ∠ bad, BC intersects at E. if ∠ EAO = 15 °, then the degree of ∠ BOE is______ Degree
- 10. 1. Given x + 1 / x = 4, then the value of X & sup2; + 1 / X & sup2; is () A. 12 b.1/2 c.16 D. uncertain 2. Given x = 2009, y = 2010, then (x + y) · X & sup2; + Y & sup2 / / X quartic - y quartic equals () 3. If x / 3 = Y / 4 = Z / 7, then the value of 3x + y + Z / y is ()
- 11. [1]1,3,7,13,21. Note that the functional relation between the nth number and N is [] [2] If the average of the first five numbers is 8 and the average of the last five numbers is 10, then the median of the nine numbers is []
- 12. Write any three digit number to meet the following requirements: 1. The number of hundred is larger than that of one 2. Exchange hundreds and ones, and subtract decimals from large numbers 3. Exchange the hundreds and individual digits of the difference, and add with the difference between the large number and the decimal It turns out to be 1089 every time. Why?
- 13. (square of 2 + 1) (4th power of 2 + 1) (8th power of 2 + 1) (16th power of 2 + 1) =?
- 14. The sum of two plus one multiplied by the square of two plus one multiplied by the square of two plus one multiplied by the square of two plus one multiplied by the square of two plus one multiplied by eight multiplied by two plus one multiplied by 16 multiplied by two plus one multiplied by 32 multiplied by two
- 15. (1 + 2 / 1) (square of 1 + 2 / 1) (square of 1 + 2 / 1) (octagonal of 1 + 2 / 1) + pentagonal of 2 / 1 +? Wrong. At the end of the list is + 2's 15 / 1 =?
- 16. Find the value of: (5 + 1) (the square of 5 + 1) (the square of 5 + 1) (the square of 5 + 1) (the octagon of 5 + 1)
- 17. (2 + 1) (the square of 2 + 1) (4 of 2 + 1) (8 of 2 + 1) (16 of 2 + 1) (32 of 2 + 1) (64 of 2 + 1) + 1? fast
- 18. 1 / 5 + 4 / (1 * 5) = 1,1 / 6 + 4 / (2 * 6) = 1 / 2,1 / 7 + 4 / (3 * 7) = 1 / 3,1 / 8 + 4 / (4 * 8) = 1 / 4
- 19. There is a group of numbers in regular order. 2.6.10.14. How to express the nth number in algebraic formula
- 20. Given a = 5, find the value of the algebraic formula (A-4) / (a ^ 2-9) divided by 1 / (A-3) multiplied by (a ^ 2 + 2a-3) / (a ^ 2-8a + 16) Given a = 5, find the value of the algebraic formula (A-4) / (a ^ 2-9) divided by 1 / (A-3) multiplied by (a ^ 2 + 6A + 9) / (a ^ 2-8a + 16)