The square of (1 + 3Y) (3y-1) - 3 (1 + 2Y) (2y-1) + (4Y + 1) =?

The square of (1 + 3Y) (3y-1) - 3 (1 + 2Y) (2y-1) + (4Y + 1) =?

The square of (1 + 3Y) (3y-1) - the square of 3 (1 + 2Y) (2y-1) + (4Y + 1)
=9y²-1-3(4y²-1)+(16y²+8y+1)
=9y²-1-12y²+3+16y²+8y+1
=13y²+8y+3