If the m-th power of 3a and the 2-th power of B are similar to the n-th power of 2 / 3AB, then the sum of the two terms is ()

Because the m power of 3a, the 2 power of B and the n power of 2 / 3AB are similar terms
So the number of corresponding letters should be equal
So m = 1, n = 2
So the sum of the two terms is the second power of 11 / 3AB

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