Place a 7.9kg cube solid iron block in the center of a square horizontal table with an area of 0.5m2. Calculate the pressure of the iron block on the table (ρ Fe = 7.9 × 103kg / m3, g = 10N / kg) I'm a sophomore. Please write like a sophomore I have to write it myself

The volume of iron block v = m iron / ρ iron = 7.9 / (7.9 * 10 ^ 3) m ^ 3 = 1 * 10 ^ - 3M ^ 3
The side length of cube iron block is a = 0.1M, and the area is s = a ^ 2 = 0.01M ^ 2
The pressure of iron block on table top P = m iron * g / S = 7.9 * 10 / 0.01 = 7900pa

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