Given that the equation x minus 6x + q = 0 to the second power can be reduced to the form of (X-P) square = 7, then what can the square of X - 6x + P = 0 be reduced to

Given that the equation x minus 6x + q = 0 to the second power can be reduced to the form of (X-P) square = 7, then what can the square of X - 6x + P = 0 be reduced to

The square of x-6x + q = (X-P) - 7 = 0
That is: the square of x-6x + q = the square of x-2px + (the square of p-7)
That is: - 6 = - 2p, q = the square of P - 7
We get: P = 3, q = 9-7 = 2
So: the square of X - 6x + P = 0, that is: the square of X - 6x + 3 = 0
Square of (x-3) + 3-9 = 0
That is, the square of (x-3) = 6