Who can help me to make this logic test simple? Y = a non B non CD + a non BC non D + a non BCD + AB non C non D + AB non CD + ABC non D + ABCD non + ABCD

The first and third items are combined as: a non CD
The second and sixth items are combined as: BC non-d
The fourth and fifth items are combined as: ab non-d
Items 7 and 8 are combined as ABC
The final results are as follows
Y = a non CD + BC non D + AB non D + ABC

RELATED INFORMATIONS

1. Please help simplify the Boolean algebra formula (non-A + non-B + non-C) (a + B + C) Thank you first! I'm a freshman in senior high school. I don't understand terms
2. Please use Boolean algebra to calculate and simplify 20 + 16
3. If the line segments a, ∠ a are known, find out the triangle ABC so that ∠ C = 90 °, AC = a, ∠ a = ∠ A. when drawing with ruler and gauge, trace is needed and urgent Be careful
4. The angle β and the line segments a and B are known. How many triangles can be made by using a ruler to make the angle B = angle β, BC = a, AC = B? Angle β is an acute angle Line segment a is longer than B Better have a picture!
5. Given the line segments a, B and angle α, find the triangle ABC so that angle a = angle α, the opposite side of angle a is a and the other side is B Is there two ways to solve this problem? If so, please explain why
6. In known RT triangle ABC, angle c = 90 degree, angle B = 30 degree
7. Known RT triangle ABC, angle c = 90 degrees, angle B = 30 degrees. 1, ruler drawing please God
8. In the triangle ABC, ab = 10, BC = 16, ad = 6, then AC= I'm a wise man. If my questioning puzzles you, my IQ is 140
9. Given: line segments a and B, find: triangle ABC, so that ∠ C = 90 degrees, AC = a, BC = B
10. As shown in the figure, given the line segments C and B (c > b), calculate: △ ABC, so that ∠ C = 90 °, ab = C, AC = B. (ruler drawing)
11. Please help simplify the value of Boolean algebra A + B + C. (B + D),
12. (non-A + non-B + non-C) (a + B + C) reduction (Boolean algebra) How to simplify AD + BC not D + C (not a + not b) A non B non C + a non BC + AB non C + ABC + non a non BC + a non C
13. Simplifying y = ABCD + abd + BCD + ABC + BD + BC by algebraic method
14. Karnaugh map simplification Q3\Q2 0 1 0 0 X 1 X 1^X Is it right to simplify Q2 + Q3 or Q2 or Q3, or take the simplest Q2 or Q3?
15. Karnaugh map simplification To simplify the following logic functions, it is necessary to draw Karnaugh map and write the simplest and or expression F='(ABC)+A'BCD+A'B+A'BC+B'C This' (ABC) and a'B, like this one, don't all contain ABCD, how to draw a picture?
16. Why can some squares be circled repeatedly when Karnaugh map is simplified?
17. How to simplify Karnaugh Map Using Karnaugh map to simplify y (a, B, C, d) = ∑ (0,2,6,7) + ∑ D (8,10,14,15)
18. Use Karnaugh map to simplify the following questions (1)Y（A,B,C）=∑m( 0,3,4,7 ) (2)Y（A,B,C）=∑m( 0,1,2,3,6,7 ) (3)Y（A,B,C,D）=∑m( 1,3,8,9,10,11,14,15 ) (4)Y（A,B,C,D）=∑m( 0,2,4,5,7,8 )+∑d(10,11,12,13,14,15)
19. On the reduction of irrelevance in Karnaugh Map Karnaugh map is shown in the figure. If the grid corresponding to the minimum terms M13, M15 and M11 is regarded as 1 according to the independent terms, the maximum bounding circle can be obtained, and L = D can be obtained. If the independent terms are not used, the maximum bounding circle can be obtained The answer is not the same at all. May I ask what kind of simplification method is right?
20. Using Karnaugh map to find the logic function f (a, B, C, d) = ∑ m (1,4,9,13) + ∑ D (5,6,7,11,15) Karnaugh map and simplification process, urgent