If the formula | x + 1 | + | X-2 | takes the minimum value, find the value range of X. if the formula | x + 1 | + | X-2 | takes the minimum value,

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• 1. Mathematics problem of grade one in junior high school: rewrite the following equation into the form of Y represented by the formula containing X Rewrite the following equation to express y with an equation containing X ①3/2X+2Y=1 ②1/4X+7/4Y=2 3、5X-3Y=X+2Y ④2(3Y-3)=6X+4
• 2. [mathematics problem of grade one in junior high school] (simplification) calculation - A + 2 (A-1) - (3a + 5)
• 3. When Hai Xu solved the equation 5x-1 = () x + 3, he misread the number at "()" and solved x = - 43, then he regarded "()" as () A. 3B. -1289C. -8D. 8
• 4. 5 x-x = 3.25, the value of the unknowns which make the left and right sides of the equation equal is () Please help!
• 5. If 5 (x + 2) = 2A + 3 and (3a + 1) a / 5 = (5x-3) a / 5 are the same solution equations about X, then a =? I'm sorry, I wrote it wrong. It should be 5 (x + 2) = 2A + 3 and (3a + 1) x / 3 = (5x-3) a / 5. If a =?
• 6. Judge which number in brackets is the flat of the solution of the previous equation 5x-15 = 2 / 2 X-1 (x = 3, x = 7) 2 (x + 0.5) = x + 2 (x = - 3, x = 1) X Judge which number in brackets is the solution of the previous equation 5x-15 = 2 / 2 X-1 (x = 3, x = 7) 2（x+0.5）=x+2 （x=-3,x=1） The square of X - 3x = 4 (x = 4, x = 1)
• 7. The solutions of the equations 3x + 5Y = m + 2,2x + 3Y = m are suitable for the equations x + y = 2, and the values of M & sup2; - 2m + 1 are obtained
• 8. Find the value of (x + y) (2x-y) - (x + 2Y) (x-2y), where x = 3, y = 4 Such as the title
• 9. : x + 2Y less than or equal to 3, x greater than or equal to 0, y greater than or equal to 0, find the maximum value of 2x + y
• 10. If the cubic power of X + (m-1) the quadratic power of X + X + 2 has no quadratic term, M =?
• 11. It is known that the solutions of binary linear equations x + 2Y = K + 21 2x + y = 1 are opposite to each other, then the reciprocal of K is K
• 12. (1-1 / 2 of the square) (1-1 / 3 of the square)... (1-1 / 2013 of the square) = to simplify the calculation process
• 13. Calculation: √ 9 - | - 2 | + (1 / 3) minus one + (- 1) 2013 square
• 14. Junior one mathematics super problem! BD is the middle line of △ ABC, CE is perpendicular to BD at e, AF is perpendicular to BD, and the extension line of BD is at F. please specify: be + BF = 2bd
• 15. There is a Z-shaped road ABCD in the park, in which ∠ B = ∠ C, there are three small stone benches e, m, f beside AB, BC, CD, and be = CF, M is the midpoint of BC. Try to explain the reason why the three stone benches e, m, f are just in a straight line
• 16. When a = 3, ax + X-1 = 5, then when a = - 3, ax - X=__ Note: square is the square of X
• 17. The department store sold a commodity. In January, it sold a piece and made a profit of 30000 yuan 4 yuan, but the sales volume increased by 5000 pieces compared with January, so the profit was y yuan more than January (1) Finding the relation between Y and a=_________ )
• 18. Two problems of mathematics in grade one of junior high school~ The current price of a certain brand of laptop is x yuan, which is 10% lower than that of last year______ (answer with polynomial) Let a B C denote an integral, and A-B = 3x square - 2x + 1, B-C = 4-2x square, then a-C=_________
• 19. 1. M power of a × n power of a (m, N, I am a positive integer) two Please fill in ">" < "or" = "on the line (1) The second power of 4 + the second power of 3______ 2x4x3 (2) The second power of (- 3) + the second power of 1_____ 2x(-3)x1 (3) The second power of (- 2) + the second power of (- 2)______ 2x(-2)x(-2) == and then mainly the following questions Through observation and induction, write a general conclusion that can reflect this law =The first problem is wrong, m, n is a positive integer And pay attention to the second question. Through observation and induction, we can draw a general conclusion that can reflect this law.
• 20. Let x = 2 be the solution of AX + by = 6, then 2a-3b-2=_______ y＝-3