Solving binary linear equations: (substituting elimination method)! （1）{x-y=3,① （2 ）{2s=3t,① {3x-8y=14；② {s= 2t+5/3；②

The solution X-Y = 3, 1 3x-8y = 14, 2 from 1: x = y + 3, 3 (y + 3) - 8y = 14, i.e. - 5Y = 5  y = - 1, y = - 1 into 3: x = 2  x = 2, y = - 12s = 3T, 1 s = 2T + 5 / 3, 2 from 2 into 1: 2 (2t + 5 / 3) = 3T  4T + 10 / 3 = 3T  t = - 10 / 3, and T = - 10 / 3 into 1: 2S = 3 × (- 1

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