Judgment: for any rational number, there are (a + b) &# 178; ≠ A & # 178; + B & # 178; But what if a and B are equal to 0 and 1 respectively?

Orange here, hello
For any rational number, there are (a + b) &# 178; ≠ A & # 178; + B & # 178; (×)
Because when a and B are equal to 0, (a + b) &# 178; = A & # 178; + B & # 178; = 0

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