Given that 14a2 + 9b2 − a + 12b + 5 = 0, find the value of (a − 2) 2A2 − B2

Given that 14a2 + 9b2 − a + 12b + 5 = 0, find the value of (a − 2) 2A2 − B2

14a2+9b2−a+12b+5=0,14a2-a+1+9b2+12b+4=0,(12a-1)2+(3b+2)2=0,∴12a-1=0,3b+2=0,∴a=2,b=-23,∴(a−2)2a2−b2=0.