Given x ^ 2 + 4Y ^ 2-4x + 8y + 8 = 0, find x + y
(x²-4x+4)+(4y²+8y+4)=0
(x-2)²+4(y+1)²=0
Then:
X-2 = 0 and y + 1 = 0
The results are: x = 2, y = - 1
x+y=1
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