After connecting the two bulbs marked with 220 V 200 W and 220 V 40 W in series into the 380 V circuit, what will burn out is, help. 0 points Then I calculate that the IE 200 / 220 of a is 0.909, the IE of B is 40 / 220 = 0.182, the resistance of a is 242, the resistance of B is 1210, the total current of the circuit is 380 / (1210 + 242) = 0.26, because 0.26 is greater than 0.909 and 0.1818, so the two lamps are burned out. What's wrong with me? After connecting the two bulbs marked with 220 V 200 W and 220 V 40 W in series into the 380 V circuit, what will burn out is, help Then I calculate that the IE 200 / 220 of a is 0.909, the IE of B is 40 / 220 = 0.182, the resistance of a is 242, the resistance of B is 1210, the total current of the circuit is 380 / (1210 + 242) = 0.26, because 0.26 is greater than 0.909 and 0.1818, so the two lamps are burned out. What's my fault?

After connecting the two bulbs marked with 220 V 200 W and 220 V 40 W in series into the 380 V circuit, what will burn out is, help. 0 points Then I calculate that the IE 200 / 220 of a is 0.909, the IE of B is 40 / 220 = 0.182, the resistance of a is 242, the resistance of B is 1210, the total current of the circuit is 380 / (1210 + 242) = 0.26, because 0.26 is greater than 0.909 and 0.1818, so the two lamps are burned out. What's wrong with me? After connecting the two bulbs marked with 220 V 200 W and 220 V 40 W in series into the 380 V circuit, what will burn out is, help Then I calculate that the IE 200 / 220 of a is 0.909, the IE of B is 40 / 220 = 0.182, the resistance of a is 242, the resistance of B is 1210, the total current of the circuit is 380 / (1210 + 242) = 0.26, because 0.26 is greater than 0.909 and 0.1818, so the two lamps are burned out. What's my fault?

"Because 0.26 is greater than 0.909 and 0.1818, the two lights are burned out. What's my fault?" take a closer look. Why is 0.26 greater than 0.909