The cuboid is 12 cm long and 8 cm high. The sum of the areas of the two sides of the shadow is 200 square cm. What is the surface area of the cuboid?

Let the width of the cuboid be a centimeter, then 12a + 8A = 200 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 20A = 200 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; a = 10, so the surface area of the cuboid is: (10 × 12 + 10 × 8 + 8 × 12) × 2 = (120 + 80 + 96) × 2 = 296 × 2 = 592 (square centimeter)

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