I'm going to buy a piece of wood, 5cm thick, 13cm wide and 4m long. How much is the cube?

I'm going to buy a piece of wood, 5cm thick, 13cm wide and 4m long. How much is the cube?


0.026 M3



·I have a piece of wood 150 cm in length, 9 cm in width and 6 cm in height. How should I calculate its cubic number,


The cube is the unit to the third power
150cm*9cm*6cm=8100cm^3
Cube = length * width * height



2 meters long wood, 12 cm in diameter. How many pieces do you need to have one side? Please 3Q
Get angry in a hurry


The volume of each round wood is 0.022608 cubic meters, so the volume of one square wood is 44.2321. If the volume of each square wood is 0.0288 cubic meters, the volume of one square wood is 34.7



Simple operation of 99.9 + 99.9?
To calculate


99.9+99.9
=(100-0.1)+(100-0.1)
=200-0.2
=199.8



Dy / dx-y = x satisfies the special solution of Y (0)


dy/dx-y=x
The homogeneous solution is y = CE ^ X
The special solution is y = - X-1
So the general solution is y = CE ^ x-x-1
y(0)=?



1: 1. What is the empirical value of cement slurry density (ordinary 42.5 cement)
This seems to need field test to know, but I just calculated the ratio roughly. Who can provide the algorithm or empirical value


Generally, it is in the range of 1.50 ~ 1.53. I use po.42.5 cement here, and the density is 1.51 when the water cement ratio is 1:1



Given that the sequence {an} satisfies A1 = 1An = 2An − 1 + 1, n ≥ 2, find the general term formula of {an} and its first n terms and Sn


∵ when n ≥ 2, an = 2an-1 + 1, ∵ an + 1 = 2 (an-1 + 1) an + 1An − 1 + 1 = 2, ∵ sequence {an + 1} is equal ratio sequence, and the common ratio is 2, and ∵ A1 = 1, ∵ a1 + 1 = 2 ∵ an + 1 = 2n, an = 2n-1sn = 21-1 + 22-1 + +2n-1=2(1−2n)1−2-n=2n+1-2-n



If the function f (x) = (2a-1) ^ x is a decreasing function on R, then the value range of a is


F (x) = (2a-1) ^ x is a decreasing function on R
So there are: 0



How to calculate 9.87 * 7.2-0.987 simply


9.87*7.2-0.987
0.987x7.2x10-0.987
=0.987x(72-1)
=0.987x(70+1)
=0.987x70+0.987
=69.09+0.987
=70.077



Cut a cylinder whose bottom diameter is 6cm and height is 10cm into two half cylinders along the bottom diameter. Find the sum of the surface area of one half cylinder (as shown in the figure)
Product


The circumference of the bottom surface of the cylinder is 3.14 * 6 = 18.84 (CM), the side area of the cylinder is 18.84 * 10 = 188.4 (cm ~ 2), the side area of the half cylinder is 188.4/2 + 6 * 10 = 154.2 (cm ~ 2), and the sum of the upper and lower bottom areas of the half cylinder is 3.14 * (6 / 2) ^ 2 = 28.26 (cm ~ 2)