Given that point P is in the plane of △ ABC, if vector PA + vector Pb + 2 and vector PC = 0, then s △ PAB: s △ PBC =? Change one: if vector PA + 2 vector Pb + 3 vector PC = 0, then s △ PAB: s △ PBC =? Change two: if 2 vector PA + 3 vector Pb + 4 vector PC = 0, then s △ PAB: s △ PBC =?

You can have a look at this

8x + 1 / 3 = 2 / 3 solution equation

8x+1/3=2/3
24x+1=2
24x=1
x=1/24

If x and y satisfy the constraint condition {X-Y + 1 > = 0, x + Y-3 = 0}, then z = the minimum value of 3x-y

Draw a straight line X-Y + 1 = 0, x + Y-3 = 0, x + 3y-3 = 0
The three intersections are (1,2) (0,1) (3,0)
When the above three groups of numbers are brought into Z = 3x-y, we can see that if (0,1) is brought in, the minimum value of Z is - 1

What is the size relationship between a positive integer a and its opposite number - A and reciprocal 1 / a

Positive integers a > = 1,00, - a = 1 / a > - A

Reading materials: if the two real roots of the quadratic equation AX2 + BX + C = 0 (a ≠ 0) are X1 and X2, then there is the following relationship between the two real roots and the coefficients of the equation: X1 + x2 = - B / A, x1x2 = C / A

Root formula B ^ 2-4ac
x1+x2=[-b+√b^2-4ac+(-b-√b^2-4ac)]/2a=-2b/2a=-b/a
x1x2=(-b+√b^2-4ac)/2a·(-b-√b^2-4ac)/2a=[b^2-(b^2-4ac)]/4a^2=4ac/4a^2=c/a

If f (x) = the square of X-1, then f (X-2) is zero?

f(x-2)=(x-2)^2-1=(x-2+1)(x-2-1)=(x-1)(x-3)
So the zeros are X1 = 1 and X2 = 3

If a = {x | - 3 ＜ x ＜ 1}. And the solution set of inequality 2x & # 178; + ax + B ＜ 0 is B. find the value of a and B Online, etc,

From the problem, x = - 3, x = 1 is the equation
Two roots of 2x & # 178; + ax + B = 0
therefore
2 * 3 * 3-3a + B = 0,2 * 1 * 1 + A + B = 0; solution a = 4, B = - 6

It is known that the image of quadratic function y = AX2 + BX + C passes through points (1,0), (- 5,0), and the ordinate of the vertex is 92

The image of ∵ quadratic function y = AX2 + BX + C passes through points (1,0), (- 5,0), the axis of symmetry is x = - 2, the ordinate of ∵ vertex is 92, the ordinate of ∵ vertex is: (- 2,92), let the analytic formula of the quadratic function be y = a (x + 2) 2 + 92, ∵ 0 = a (1 + 2) 2 + 92, the solution is a = - 12, ∵ the analytic formula of the quadratic function is y = - 12x2 − 2x + 52

The usage of the unknown x
Please be concise
Easy to understand

The letter also represents a number. Its size is unknown. It may be 2, or it may be letters other than 5.. x, such as a, B, etc
X is generally used in the equation:
12+x=120
X=120-12
X = 108 - here x is 108
In addition, if there is only a letter problem, such as: I bought n pencils, paid X Yuan, and used (NX)
Yuan
It has algebraic significance as well

Given that x + y = a, xy = B (B is not equal to 0), the following formulas are expressed by formulas containing a and B
x^4+y^4=?

X square + y square = a ^ 2-2b
x^4+y^4=(a^2-2b)^2-2b^2

Given that point P is in the plane of △ ABC, if vector PA + vector Pb + 2 and vector PC = 0, then s △ PAB: s △ PBC =? Change one: if vector PA + 2 vector Pb + 3 vector PC = 0, then s △ PAB: s △ PBC =? Change two: if 2 vector PA + 3 vector Pb + 4 vector PC = 0, then s △ PAB: s △ PBC =?