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There are 165 students in Grade 6. One fifth of boys is equal to one sixth of girls. How many boys and girls are there in Grade 6?
There are 165 sixth grade students, one fifth of boys is equal to one sixth of girls
The ratio of boys to girls is 6:5, and the ratio of boys to girls is 6 / (5 + 6) = 6 / 11
So the number of boys is 165 * 6 / 11 = 90
The number of female students is 165-90 = 75
If x = 2, the value of the algebraic formula AX3 + BX + 1 is 6, then when x = - 2, the value of the algebraic formula AX3 + BX + 1 is 6______ ．
When ∵ x = 2, the value of the algebraic formula AX3 + BX + 1 is equal to 6, substituting x = 2 into 8A + 2B + 1 = 6, ∵ 8A + 2B = 5, substituting x = - 2 into AX3 + BX + 1 to get: - 8a-2b + 1 = - (8a + 2b) + 1 = - 5 + 1 = - 4; so the answer is: - 4
One quarter of the number of boys is equal to two fifths of the number of girls
x/4=2/5y x:y=8:5
The ratio of men to women is 8:5
(38 times 56 times 64) divide by (19 times 28 times 16)
(38 by 56 by 64) divided by (19 by 28 by 16)
=38/19*56/28*64/16
=2*2*4
=16
There are three schools: school a, School B and school C. 12% of the number of school a is equal to 13% of the number of School B and 37% of the number of school C. It is known that school C has 120 more students than school A. how many students are there in the three schools?
The number of students in school a: 120 △ 37-1, = 120 △ 76-1, = 120 △ 16, = 720; the number of students in school B: 720 × (12 △ 13), = 720 × 32, = 1080; the number of students in school C: 720 + 120 = 840; the number of students in three schools: 720 + 840 + 1080 = 2640
The positions of the corresponding points of rational numbers a, B and C on the number axis are shown in the figure: try to simplify the following formula: | a-c | - | C-B | - | B-A | + 2 | a + B |
According to the meaning of the title: C < a < 0 < B, and | a | C | B | a-c > 0, C-B < 0, B-A > 0, a + b > 0, then the original formula = a-c + c-b-b + A + 2A + 2B = 4A
The average number of a, B and C is 75. It is known that a: B = 4:5, a: C = 2:3. What are the numbers of a, B and C respectively?
Calculated, you are wrong, should be set to 6x, 4x, 5x, ha ha, but thank you!
Let a be 4x, then B be 5x, C be 6x, 4x + 5x + 6x = 75 × 3, the solution is x = 15, so a is 60, B is 75, C is 90
The sum of all real numbers whose absolute value is less than 5 is___ ．
For all real numbers whose absolute value is less than 5, the numbers whose distance from the point on the number axis to the origin is less than 5 are opposite to each other and appear in pairs, so the sum of them is 0
Three fifths of a number is 15 less than five sixths of 120. Find this number
This number
(120x5/6-15)÷3/5
=85÷3/5
=425/3
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When Xiaofang solved the equation (2x + 1 / 5) - 1 = x + A / 2 to remove the denominator, the left 1 of the equation was not multiplied by 10, so the solution of the equation was x = - 4
Try to find the value of a and find the correct solution of the equation
2x+1/5-1=x+a/2
2x-4/5=x+a/2
2x-x=4/5+a/2
x=8+5a/10
∵x=-4
∴8+5a/10=-4
a=-48/5
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