It is known that a ＜ B (AB is not equal to 0), try to compare the size of 1 / A and 1 / b

It is known that a ＜ B (AB is not equal to 0), try to compare the size of 1 / A and 1 / b

Because a < B (AB is not equal to 0) is known,
1. If AB 0, b > 0, then 1 / a > 1 / b;
B: If a

If a ＞ 0 and a ≠ 1, M = (1 + A ^ n) (1 + a) ^ n, n = 2 ^ (n + 1) * (a ^ n) (n ∈ n *), then the size relation of M and N is ()
A 、M＞N
B、M＜N
C、M=N
D. Not sure

If a ＞ 0 and a ≠ 1, M = (1 + A ^ n) (1 + a) ^ n, n = 2 ^ (n + 1) * (a ^ n) (n ∈ n *), then the size relation of M and N is (d)

If a > b > C is known, if one part of A-B plus one part of B-C is greater than or equal to one part of a-C, the maximum or minimum value of M can be obtained

Known: a > b > C, so A-B > 0, B-C > 0, a-c > 0
From 1 / (a-b) + 1 / (B-C) = > m / (A-C), it can be seen that if M = C, the value of a-C is equal to zero
The minimum value of M is 0

There are five natural numbers with the largest number of divisors within 100. What are they?

① If there is exactly one prime factor, then the largest divisor is 26 = 64, 6 + 1 = 7 (pieces), 64 has 7 divisors; ② if there are exactly two different prime factors, then the largest divisors are 23 × 32 = 72 and 25 × 3 = 96, (3 + 1) × (2 + 1) = 12 (5 + 1) × (1 + 1) = 1272 and 96, each with 12 divisors; ③ if there are exactly three different prime factors, then the largest divisors are 22 × 3 × 5 = 60 and 22 × 3 × 7 = 8 4 and 2 × 32 × 5 = 90, their divisors are: (2 + 1) × (1 + 1) × (1 + 1) = 12, so 60, 84, 90 each have 12 divisors. So the natural numbers with the most divisors within 100 are 60, 72, 84, 90 and 96, they all have 12 divisors

7/9x(-8/9)+2/9x(-8/9) 2/3x(-5/8)-(-1/3)x(-5/8)
7 / 9x (- 8 / 9) + 2 / 9x (- 8 / 9) 2 / 3x (- 5 / 8) - (- 1 / 3) x (- 5 / 8) - 9 divided by 3 + (1 / 2-2 / 3) X12 + 3_

7/9x(-8/9)+2/9x(-8/9)=(-8/9)×（7/9+2/9）=-8/92/3x(-5/8)-(-1/3)x(-5/8)=(-5/8)× （2/3+1/3）=-5/8-9÷[3+(1/2-2/3)x12+3 ²]=-9÷[3+(-4)+9] =9/8

50+49-48-47+46-45-44-43+… -4-3+2+1=?
There's a vertical!

There are 50 numbers, 50 + 1 + 51, 49 + 2 = 51, 25 groups in turn, so 25 * 51 = 1275

If {an} is known to be an increasing sequence and an = n & sup2; + λ n is constant for any (n ∈ n *), then the value range of real number λ A is less than - 3, B is greater than 0, C is greater than - 2 and D is greater than - 3

a(n+1)-a(n)=2n+1+λ
If {an} is a sequence of increasing numbers, then it holds
2n+1+λ>0（n>=1)
Then λ > - 2N-1 (n > = 1)
Obviously, the maximum value of - 2N-1 is - 3. If the above formula is constant, then λ > - 3

If the number a is divided by 5 and more than 3, and the number B is divided by 5 and more than 2, then the sum of the two numbers a and B is divided by 5, what is the remainder? What is the difference between the two numbers a and B divided by 5, what is the remainder? What is the product of the two numbers a and B divided by 5, and what is the remainder?

Sum remainder 0
Difference 1
Surplus 1

Which is the smallest among 9 out of 13, 36 out of 48, 45 out of 50, 45 out of 70

45/70

Parametric equation formula of conic curve
Circle, ellipse, etc

The parametric equation of a circle x = a + RCOs θ y = B + rsin θ
The parametric equation of ellipse x = ACOS θ y = bsin θ