1. If (8x) 4 power = 36 power of 2, then x =? 2. If 2n power of x = 3, then 10N power of x =? 3. Given X-Y = a, then the third power of (3x-3y) =? 4. The eighth power of (- 1 / 9) · - the eighteenth power of (- 3) =? 5. (- 3 / 4) to the power of 2008 · (1 / 3) to the power of 2008 =? 6. If the square of (n power of 9) = 20 power of 3, find the value of n 7. One change: if the nth power of 2.8 and the nth power of 16 are equal to the 36th power of 2, find the value of n; 8. Bivariate: given that the nth power of 8 is 5, the m power of 4 is 7, find the value of 4m + 6N power of 2 9. If the m power of a is 3 and the n power of a is 4, what is the value of 3M + 2n power of a?

1. If (8x) 4 power = 36 power of 2, then x =? 2. If 2n power of x = 3, then 10N power of x =? 3. Given X-Y = a, then the third power of (3x-3y) =? 4. The eighth power of (- 1 / 9) · - the eighteenth power of (- 3) =? 5. (- 3 / 4) to the power of 2008 · (1 / 3) to the power of 2008 =? 6. If the square of (n power of 9) = 20 power of 3, find the value of n 7. One change: if the nth power of 2.8 and the nth power of 16 are equal to the 36th power of 2, find the value of n; 8. Bivariate: given that the nth power of 8 is 5, the m power of 4 is 7, find the value of 4m + 6N power of 2 9. If the m power of a is 3 and the n power of a is 4, what is the value of 3M + 2n power of a?

The result of question 1 is (8x) ^ 4 = (2 ^ 9) ^ 4
So we have 8x = 2 ^ 9
x=2^6=64
2. The 10nth power of x = the 5th power of (2nth power of x) = the 5th power of 3
The third power of question 3 (3x-3y) = the third power of (3a) = 9A ^ 3
Original formula of 4 questions = (1 / 9) ^ 8 * 3 ^ 18
=(1/9*3)^8*3^10
=(1/3)^8*3^10
=(1/3*3)^8*3^2
=3^2=9
Original formula of 5 questions = (3 / 4) ^ 2008 * (4 / 3) ^ 2008
=(3/4*4/3)^2008
=1
6 questions n = 5
From the meaning of question 7, we get 2 * (2 ^ 3) ^ n * (2 ^ 4) ^ n = 2 ^ 36
2^1+3n+4n= 2^36
So 1 + 3N + 4N = 36
n=5
Question 8 is obtained by n power of 8 = 5 and m power of 4 = 7
2^3n=4 2^2m=7
So we have 2 ^ 4m + 6N
=2^4m*2^6n
=2^2m*2^2m*2^3n*2^3n
=7*7*4*4
=784
9 questions are obtained from the meaning of the questions
a^3m+2n=(a^m)^3*(a^n)^2=3^3*4^2=9*8=72
Hello, landlord, if there is any mistake, please put forward. Pure hand fight. Please accept

1. Given that the square of a + BC = 14, the square of B + 2BC = - 6, then the square of 3 * a + the square of 4 * B - 5BC=
2. If a + B + C = 0, then (a + b) (B + C) (c + b) + ABC
3. Given x = 1999, then the absolute value of (4x-5x + 1) - 4 * (the square of X + 2x + 2) + 3x + 7

1) I don't understand
2)（a+b）（b+c）（c+b）+abc =(a+b+c)(ab+bc+ac)=0
3) (4x-5x + 1)? Or (4x squared-5x + 1)?
If it is (4x-5x + 1), the value is - 15992002
If it is (4x squared - 5x + 1), the value is - 19990

As shown in the figure, the length of the ladder ABCD, ad ‖ BC, ∠ B = 45 °, C = 120 ° AB = 8 is calculated

Ad ∥ BC, ∠ B = 45 °, AE is perpendicular to BC through a, because AB = 8, so AE = 4 pieces of 2, ∠ C = 120 ° can be calculated, ∠ d = 60 ° can be calculated, CD = 2 pieces of 6

1 / 167 * (3 and 3 / 5 * 25 + 38.125 * 6 and 2 / 5)

=1/167*(18/5*25+38.125*32/5)
=1/167*(18*5+7.625*32)
=1/167*(90+244)
=1/167*334
=2

Mathematical drawing function image y = 20 / X list point drawing line

This is an inverse proportion function. It is suggested to refer to the textbook of grade 3 of junior high school

As shown in the figure, diamond ABCD, ∠ bad = 120 °, point m is the point on BC, and point n is the point on CD. If ∠ amn = 60 °, try to judge the shape of △ amn and explain the reason (please use the method of congruent triangle)

A: △ amn is an equilateral triangle. It is proved that connecting AC with Mn at point F, crossing point m as me ‖ AC with ab at point E, in ∵ rhombic ABCD, ∵ bad = 120 °, ∵ ABC and △ ACD are equilateral triangles, ∵ BCD = 120 °, ∵ AB = BC, ∵ B = 60 °, ∵ BME are equilateral triangles, ∵ EM = BM = be, ∵ BEM = 60 °, ∵ AEM = 120 °, ∵ AEM = ∵ BCD, ∵ ab-be = bc-bm, i.e., AE = MC, ? AMC are equilateral triangles In △ AEM and △ MCN, 1 ＝ 2ae = MC ∠ AEM = MCN, ｜ △ AEM ≌ △ MCN (ASA), ｜ am = Mn, ≌ amn = 60 ° and ｜ amn = 60 ° are equilateral triangles

Example: 17km = 17 times 10 to the third power = 1.7 times 10 to the fourth power=____________ =_____________ km

1. The distance between target and radar is s = VT = 3 × 10 to the fifth power km / s × (4 × 10 to the negative fourth power s) / 2 = 60km
2、C=λf
Frequency f = C △ λ = 8 power of 3 × 10 m / s △ 6 × 103m = 50000Hz = 50KHz
A: the target is 60km away from the radar. The frequency of the signal is 50KHz

There are 3 more than 12 pears for each child and 5 less than 6 pears for each child?

Nine people and 39 pears
If it is set as X person, it has: X * 3 + 12 = x * 5-6
Number of people x = 9
Pear = 9 * 3 + 12 = 39 or 9 * 5-6 = 39

The circumference of a rectangle is 36 cm and its width is 10 cm. How many cm is the length of a rectangle?

mmmlx520 ,
36 △ 2-10 = 8 (CM)

1 + 3 + 5 + 7 + 9. + 2003 + 2005 +? Simple operation

1+3+5+7+9.+2003+2005
=(1+2005)+(3+2003)+...
=2006*(2005+1)/4
=1006009