What is the calculation process of (12 / 11-6 / 5 / 4 / 3) * 48 / 1? It's the easiest way to calculate

(12/11-6/5 +4/3)*48/1
=12/11x48/1-6/5x48/1+4/3x48/1
=44-40+36
=40
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How to simplify this problem

=(30+1/28)×28/29
=(29+1+1/28)×28/29
=29×28/29+1×28/29+1/28×28/29
=28+28/29+1/29
=28+1
=29

Square of (X-6) + 9

(x^2-6)^2-6(x^-6)+9
=(x^2-6-3)^2
=(x^2-9)^2
=[(x+3)(x-3)]^2
=(x+3)^2(x-3)^2

What is the sum of two seventh of the sum of 35 plus the quotient of three fifth divided by seven tenth?

I didn't understand the question. Could you make it clear
What is the sum of 2 / 7 of 35 plus 3 / 5 divided by 7 / 10
35*2/7=10
（3/5） / （7/10）=6/7
So the answer is 10 and six out of seven

10 (3x-8) - 4 (2x + 3) = 6 (3x-4) - 4 (to be detailed)

10（3x-8）-4（2x+3）=6（3x-4）-4
30x-80-8x-12=18x-24-4
4x=64
x=16

Calculate the following questions in a simple way
4392+2997=?5364-1999=?3.25/2.5/4=?125/(50/8)=?680.99=?7.21.02=?3.72-（1.72+1.3)=?7.77+7.7+27.7=?8/9-(8/9-9/25)
38 and 3 / 4-15.38 + 61.25-4.62 =? 4.6 * 8 + 4 and 5 / 8-2 and 7 / 11-1 and 4 / 11 =?
8,17 / 32 + 5,1 / 4-6,17 / 23 + 0.75 =? 5,3 / 7 * 0.5/5,3 / 7 * 0.5 =? 5?
(5 + 5 / 9-0.8 + 2 + 4 / 9) * 125 =? 2001 * 0.64 + 2001 * 0.36 =? 64.5 * 1 / 11 + 1 / 11 * 34 + 1 / 2
Please use the disjunctive method to calculate the formula
Answer as much as you know, just answer back,

4392+2997=4392+3000-3=7392-3=7389
5364-1999=5364-2000+1=3364+1=3365
25/2.5/4=25/(2.5*4)=25/10=2.5
125/(50/8)=125*8/50=1000/50=20
68*0.99=68*(1-0.01)=68-0.68=67.32
7.2*1.02=7.2*(1+0.02)=7.2+7.2*0.02=7.2+0.144=7.344
3.72-(1.72+1.3)=3.72-1.72-1.3=2-1.3=0.7
7.7*7+7.7+2*7.7=7.7*(7+1+2)=77
8/9-(8/9-9/25)=8/9-8/9+9/25=9/25=36/100=0.36
38.75-15.38+61.25-4.62=(38.75+61.25)-(15.38+4.62)=100-20=80
4.6 * 8 + 4 and 5 / 8-2 and 7 / 11-1 and 4 / 11 = 4.6 * 8 + 4.625 - (2 and 7 / 11 + 1 and 4 / 11) = 4.6 * 8 + 4.625-4=
8:17 / 32 + 5:1 / 4-6:17 / 23 + 0.75 = 8:17 / 32 + 5:1 / 4-6:17 / 32 + 3 / 4 = 8
5 and 3 / 7 * 0.5 / 5 and 3 / 7 * 0.5 = 1
(5 5 / 9-0.8 + 2 4 / 9) * 125 = (8-0.8) * 125 = 8 * 125-0.8 * 125 = 1000-100 = 900)
2001*0.64+2001*0.36=2001*(0.64+0.36)=2001*1=2001
64.5 * 1 / 11 + 1 / 11 * 34 and 1 / 2 = (64.5 + 34.5) * 1 / 11 = 99 / 11 = 9

The sum of the largest divisor and the second largest divisor of a natural number is 111______ ．

Because 111 is odd, and odd = odd + even, the maximum divisor and the second approximation of the number must be an odd even. The maximum divisor of a number is itself. If a number has an even divisor, the number must be even, and the second approximation of an even number should be 12 of the even number

Solution equation: (4x-1 of x-1) = 1 - (8 of 1-x)

(4x-1 of x-1) = 1 - (8 of 1-x)
(4x-1)/(x-1)=1-8/(1-x)
(4x-1)/(x-1)=1+8/(x-1)
(4x-1)/(x-1)-1-8/(x-1)=0
(4x-1-x+1-8)/(x-1)=0
(3x-8)/(x-1)=0
3x-8=0
x=8/3

Calculation: (1 / 50-1) × (1 / 49-1) × (1 / 48-1) × ×(1/4-1)×(1/3-1)
Why are there 49 negative fractions multiplied

（1/50-1）*（1/49-1）*（1/48-1）*...*（1/4-1）*（1/3-1）
=（-49/50）*（-48/49）*（-47/48）*…… *（-2/3）
There are 48 negative factors, so the result is positive. The numerator of the former fraction can be reduced to the denominator of the latter fraction
=2/50
=1/25

If inequality [(1-A) * n-a] * LGA
N is any positive integer

The classification of a is discussed
1. If a is between 0 and 1, LGA is less than 0. Then [(1-A) n-a] should be greater than 0
The change is: an / (n + 1). In order to make n constant for any integer, let a be greater than the maximum value of N / (n + 1)
The maximum value of N / (n + 1) is 0 when n = 0. You can change it into 1 / (1 + 1 / N), which is easy to see. Therefore, you need a > 0
The premise of this discussion is a > 1, so the scope is a > 1
3. Because a is the true number of logarithmic function, the case of less than 0 does not exist

What is the calculation process of (12 / 11-6 / 5 / 4 / 3) * 48 / 1? It's the easiest way to calculate