As shown in the figure, it is a beautiful Pythagorean tree, in which all quadrangles are squares and all triangles are right triangles. If the side lengths of squares a, B, C and D are 3, 5, 2 and 3 respectively, then the area of the largest square e is

As shown in the figure, it is a beautiful Pythagorean tree, in which all quadrangles are squares and all triangles are right triangles. If the side lengths of squares a, B, C and D are 3, 5, 2 and 3 respectively, then the area of the largest square e is

According to the Pythagorean theorem, the area of a + B is the area of the white square on the left, the area of C + D is the area of the white square on the right, and the area of E is the sum of the areas of two white squares. So the area of E = 3 * 3 + 5 * 5 + 2 * 2 + 3 * 3 = 47. If you require the side length, they are radical 34, radical 13 (two white) and radical 47 (square E)

What is one and one tenth plus two and seven tenths divided by (three and one twelfth minus 1.125) × two and nine thirds

[one and one tenth plus two and seven tenths divided by (three and one twelfth minus 1.125)] × nine out of twenty-three
=【1.1+2.7÷47/24】×9/23
=233/94×9/23
=（230+3）/94×9/23
=90+27/2163
=90 and 27 / 2162

How to calculate a new function image if the function image is symmetric with respect to a point?
The title is y = x + 1 / X (x ≠ 0) with respect to (2,1) symmetry, to find a new analytic expression of function Ask for advice!

Let any point a (m, n) in the original image and the symmetric point B (a, b) of a with respect to (2,1) be on the new image
m+a=2*2=4,n+b=1*2=2
m=4-a,n=2-b
Bring in the original image equation 2-B = (4-A) + 1 / (4-A)
b=a-2-1/(4-a)
New analytic expression of function y = x-2-1 / (4-x)

If AB = 3cm, BC = 5cm, the area of the overlap △ DEF is ()
A. 7.5cm2B. 5.1cm2C. 5.2cm2D. 7.2cm2

If AE = x, then a ′ e = xcm, de = 5-x (CM), ∧ a ′ E2 + a ′ D2 = ED2, ∧ x2 + 9 = (5-x) 2, the solution is: x = 1.6, ∧ de = 5-1.6 = 3.4 (CM), ∧ def surface product

The earth can be seen as a sphere with a radius of 6.4 times 10 cubic km, and the latitude of Beijing is about 40 degrees. What is the angular velocity and linear velocity of the two objects at the equator and Beijing in uniform circular motion with the earth's rotation?
The angular velocity of uniform circular motion is the same, w = 2 π / (24 × 3 600) rad / S = 7.3 × 10-4 rad / s
For objects on the equator, the linear velocity V1 = ω r = 4653 M / S; for objects in Beijing, the linear velocity V2 = ω R1 = ω rcos40 ° = 3.7 × 103 M / s. The answer is this, but how can cos40 be obtained

Like a basketball turning on an upright finger, the most protruding points on both sides make a circular motion around a big circle. The closer the point is to the rotation axis, the smaller the radius of the circular motion. Because Beijing is at 40 degrees north latitude, the radius of its circular motion is equal to the radius of the earth multiplied by the cosine of 40 degrees

Please do me a favor
When someone goes from place a to place B, half of them ride a bicycle and half of them walk. When they return, they spend 1 / 3 of their time riding a bicycle and 2 / 3 of their time walking. It is known that the speed of riding a bicycle is 15 km / h, the speed of walking is 5 km / h, and the time of going is 2 hours more than that of returning

When returning, one third of the time to ride a bicycle, two thirds of the time to walk, the equation is: (2x / 15-2) * 1 / 3 * 15 + (2x / 15-2) * 2 / 3 * 5 = X2X / 3-10 + 4x / 9-20 / 3 = XX / 9 = 50 / 3x = 150, that is, the distance is 150 km

The sum of the length and width of a rectangle is 13 cm, and its circumference is______ Cm

13 × 2 = 26 (CM), a: the circumference of a rectangle is 26 cm

Calculate 1 + (- 3) + 5 + (- 7) + 9 + (- 11) +. + 2001 + (- 2003) + 2005 according to the method of rational number

1+（-3）+5+（-7）+9+（-11）+.+2001+（-2003）+2005
=-2+(-2)+(-2)+.+(-2)+2005
There are 1000 + 2 = 1002 numbers from 1 to - 2003
So the above formula = - 2 * 1002 / 2 + 2005
=-1002+2005
=2003
There are questions, please ask me!

The length of a train is 200 meters. When passing through a tunnel, the speed is 60 kilometers per hour. It takes 2 minutes from the front of the train to the rear of the train to leave the tunnel

200+X=(60*1000)/(60*60)*(60*2)
X=1800
The total length of the tunnel is 1800m

The perimeter of a rectangle is 64cm, and the ratio of length to width is 5:3. What is the area of the rectangle?

Because the perimeter of a rectangle is two lengths plus two widths, the sum of one length and one width is 64 △ 2 = 32cm
5 out of 8, the length is 20 cm
The width of 3 out of 8 parts is 12 cm
So the area of rectangle = length × width = 20 × 12 = 240cm & sup2;