Bivariate linear equation (x + 1) / 3 - (y + 2) / 4 = 0 ① (x-3) / 4 - (Y-3) / 3 = 1 / 12 ②

Bivariate linear equation (x + 1) / 3 - (y + 2) / 4 = 0 ① (x-3) / 4 - (Y-3) / 3 = 1 / 12 ②

(x + 1) / 3 - (y + 2) / 4 = 0, ① (x-3) / 4 - (Y-3) / 3 = 1 / 12, ② (1 × 12): 4 (x + 1) - 3 (y + 2) = 0 ∧ 4x-3y = 2, ③ (2 × 12): 3 (x-3) - 4 (Y-3) = 1 ∧ 3x-4y = - 2, ④ (3 × 4 - ④ × 3): 7x = 14 ∧ x = 2, substitute x = 2 into ③ to get: 8-3y = 2 ∧ y = 2 ∧

2 (X-Y) / 3 - (x + y) / 4 = - 1 / 12,3 (x + y) - 2 (2x-y) = 3, find the solution of the binary linear equation

2(x-y)/3-(x+y)/4=-1/12,
8(x-y)-3(x+y)=-1;
5x-11y=-1(1)
3(x+y)-2(2x-y)=3
3x+3y-4x+2y=3;
5y-x=3;
25y-5x=15;
14y=14;
y=1;
x=2;
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m. When n is what number, the polynomial x ^ 4-5x ^ 3 + 11x ^ 2 + MX + n can be divided by x ^ 2-2x + 1, and the quotient can be obtained

x^4-5x^3+11x^2+mx+n
=(x^2-2x+1)(x^2+ax+n)
=x^4+(a-2)x^3+(n-2a+1)x^2+(a-2n)x+n
a-2=-5
n-2a+1=11
a-2n=m
a=-3,n=4,m=-11
Remainder x ^ 2-3x + 4

Given that the inequality x + 3 + m 2-x ≥ 2 holds, we can find the value range of real number M

m≥(2-|x+3|)/|2-x|
x> When m ≥ - 1-3 / (X-2), the maximum value of - 1-3 / (X-2) in the interval is - 1, so when m ≥ - 1, x > 2 is constant
When x = 2, m takes any value, and the inequality holds
-3≤x

(A and 178 of AB; + B and 178;) + [2 - (A and 178 of AB; - B and 178;)]

(a²+b²)/ab+[2-(a²-b²)/ab]
=(a²+b²+2ab-a²+b²)/ab
=(2b²+2ab)/ab
=2(a+b)/a

The heights of triangles and parallelograms are equal, and the lengths of their bases are 4cm and 8cm. What is the area ratio of triangles and parallelograms?

1：4
S (triangle) = bottom * height / 2
S (parallelogram) = base * height

How to solve the equation that five sixths minus three x equals one third?

5/6-3x=1/3
3 x=5/6-1/3
3x=3/6
x=3/6*1/3
x=1/6

Let the tangent equation of the curve y = x ^ 4 + ax + B at x = 1 be y = X. what are the values of a and B

y'=4x^3+a
The tangent slope of y = x ^ 4 + ax + B at x = 1 is
y'|(x=1)==4+a=1, a=-3
The tangent coordinates are (1, b-2)
The tangent equation is Y - (b-2) = X-1
y=x+b-3
So B = 3

7x (- 3) x (+ 0.5) + - 12) x (- 2.6)

=-21*0.5+12*2.6=-10.5+31.2=20.7

Find the function y = sin ^ 2x + acosx + 5A / 8-3 / 2 (0

y=1-cos^2x+acosx+5a/8-3/2=-(cosx-a/2)^2+a^2/4+5a/8-1/2;
Because 0