A ^ - B ^ + 2A + () can be factorized Add integral in brackets Are there any answers other than + - 2b and 1

A ^ - B ^ + 2A + () can be factorized Add integral in brackets Are there any answers other than + - 2b and 1

Factorization process of a (2a, b) - B (2a-b)

　　a(2a -b)-b(2a-b)＝﹙a－b﹚﹙2a－b﹚

Factorization of 1-16a ^ 4B ^ 4

1-16a^4b^4
=1-(4a²b²）²
=（1-4a²b²）(1+4a²b²)
=(1+2ab)(1-2ab)(1+4a²b²)

Factorization: 16a2b-16a3-4ab2

16a2b-16a3-4ab2=4a（4ab-4a2+b2）=-4a（2a-b）2．

How does the curve X ^ 2 / 3 + y ^ 2 / 3 = 1 become a parametric equation,

Using Sin & # 178; a + cos & # 178; a = 1
x^2/3+y^2/3=1
(x/√3)²+(y/√3)²=1
Let X / √ 3 = cosa, Y / √ 3 = Sina
The parameter equation is x = √ 3cosa, y = √ 3sina (a is the parameter)

4(x-y+1)+y(y-2x)
4x^4-13x²+9

4(x-y+1)+y(y-2x)=4x-4y+4+y^2-2xy=(2-y)^2+2x(2-y)=(2-y)(2-y+2x)4x^4-13x²+9=4x^4-12x^2+9-x^2=(2x^2-3)^2-x^2=(2x^2-3+x)(2x^2-3-x)=(2x+3)(2x-3)(x+1)(x-1)

In the quadrilateral ABCD, ∠ B + ∠ C = 180, ∠ B = ∠ D, prove the quadrilateral ABC parallelogram

Because ∠ B = ∠ D, so ∠ D + ∠ C = 180 degrees (equivalent substitution), so ad parallels BC, and then connects AC. in △ ABC and △ CDA, ∠ B = ∠ D, ∠ BAC = ∠ DCA, AC = Ca, so △ ABC ≌ △ CDA, so ad = BC, so quadrilateral ABCD is a parallelogram (a group of parallelograms that are parallel and equal to each other are parallelograms)

Find the limit limx → 1 x & # 178; + 1 / X & # 178; - 1

It should be ∞

If the quadratic function y = ax + BX + C, the image and X axis intersect at two points AB, where the coordinates of point a are (- 1., 0), C (0,5), D (1,8) are on the parabola, and M is the center of the parabola
To find the analytic formula of parabola and the area of triangle MCB

(1) Substituting a (- 1,0), C (0,5), D (1,8) into y = ax & # 178; + BX + C, the solution is a = - 1, B = 4, C = 5, so the analytic formula of parabola is y = - X & # 178; + 4x + 5. (2) parabola y = - X & # 178; + 4x + 5 can be changed into y = - (X-2) & # 178; + 9, so the coordinate of M is (2,9), let y = 0, the coordinate of B is (5,0)

There are 90 students in the two classes of grade two, among which 71 are young pioneers. We also know that the number of young pioneers in class one accounts for 34% of the total number of students in this class, and that the number of young pioneers in class two accounts for 56% of the total number of students in this class______ People

If there are x people in one class, there will be 90-x people in two classes, and if there are x people in one class, then there will be 90-x people in two classes, and & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 34x + 56 (90-x) = 71, & nbsp; & nbsp; & nbsp; & nbsp; 34x + 56 (90-x) = 71, & & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp & nbsp; & nbsp; & & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; &The number of students in class two is 90-48 = 42. A: there are 48 students in class one and 42 students in class two