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As shown in the circuit diagram, the power supply voltage is 6V and remains unchanged. After s is closed, the indication of ammeter A1, A2 and A3 are 0.3A, 0.9A and 2.1a respectively. Try to find out the resistance value of resistance R1, R2 and R3
The equivalent circuit diagram is as follows: (1) the resistance of R1 is: R1 = ui1 = 6v0.3a = 20 Ω; (2) the current through R3 is: I3 = ia2-i1 = 0.9a-0.3a = 0.6A, so R3 = ui3 = 6v0.6a = 10 Ω; (3) the current through R2 is: I2 = ia3-ia2 = 2.1a-0.9a = 1.2A, so R2 = ui2 = 6v1.2a = 5 Ω
As shown in the circuit diagram, the power supply voltage is 6V and remains unchanged. After s is closed, the indication of ammeter A1, A2 and A3 are 0.3A, 0.9A and 2.1a respectively. Try to find out the resistance value of resistance R1, R2 and R3
The equivalent circuit diagram is as follows: (1) the resistance of R1 is: R1 = ui1 = 6v0.3a = 20 Ω; (2) the current through R3 is: I3 = ia2-i1 = 0.9a-0.3a = 0.6A, so R3 = ui3 = 6v0.6a = 10 Ω; (3) the current through R2 is: I2 = ia3-ia2 = 2.1a-0.9a = 1.2A, so R2 = ui2 = 6v1.2a = 5 Ω
A method for calculating the impedance of series and parallel connection of resistance, capacitance and inductance
Capacitive reactance:
Xc＝1/(2×3.14fC)
Inductive reactance:
XL＝2×3.14fL
Total impedance of resistance, capacitance and inductance in series:
Z = root sign [R square + (xl-xc) square]
Total impedance of resistance, capacitance and inductance in parallel:
Z = 1 / radical [(1 / R) square + (1 / XL-1 / XC) square]
Capacitance, resistance, inductance parallel how to calculate impedance, please describe separately, thank you~
Which is the bigger of the 9th power of 9 and the 99th power of 9
The 9th power of 9 is greater than the 99th power of 9
Their base number is 9
The index is 9-9 and 99
9＾9＞99
So the 9th power of 9 is greater than the 99th power of 9
The general formula of 11 111 1111 11111
an=[10^(n+1)-1]/9
Decomposition factor: 6x ^ 3Y ^ 2-4x ^ 2Y ^ 3 + 2x ^ 2Y ^ 2 144x ^ 2-256y ^ 2 25 * (x-1) ^ 2-10 (x-1) + 1 (2x-y) ^ 2 - (X-Y) ^ 2
6x^3y^2-4x^2y^3+2x^2y^2
=2x^2y^2(3x-2y+1)
144x^2-256y^2
=(12x+16y)(12x-16y)
=16(3x+4y)(3x-4y)
25*(x-1)^2-10(x-1)+1
={5(x-1)-1}^2
=(5x-6)^2
（2x-y)^2-(x-y)^2
=(2x-y+x-y)(2x-y-x+y)
=3x(3x-2y)
The law of series parallel circuit voltage?
The third floor is wrong!
In a series circuit, the total voltage is equal to the sum of the resistance voltages, u = U1 + U2, the current is equal everywhere, I = I1 = I2
In parallel circuit, the voltage of each branch is equal, u = U1 = U2, the total current is the sum of the currents of each branch, I = I1 + I2
Why is 1 / 2 of a + m a fraction
Explanation is not cover up, cover up is not story telling
Because the denominator of a + m has letters, it's so simple, our teacher said
Two "220W & nbsp; 60W" incandescent lamps are connected in series in the home circuit, and the total luminous power of the two lamps is ()
A. 120WB. 60WC. 30WD. 15W
The resistance of the bulb is r = u2p = (220V) 260W = 24203 Ω. When two lamps are in series, the total power of the circuit is p = u22r = (220V) 22 × 24203 Ω = 30W
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