In the stable circuit, R1 = 1 Ω, R2 = 2 Ω, R3 = 3 Ω, then the current intensity ratio I1: I2: I3 through resistance R1, R2, R3 is? The circuit diagram is as follows: R2 and R3 are in series, while R1 is in parallel~~ Why is the answer 5:3:2 or wrong? Can you give me an explanation of the process?

Because R2 and R3 are in parallel, the voltage is the same
Then I2: I3 = u / r2: U / R3 = R3: R2 = 3:2
Because R2 and R3 are connected in parallel and then connected in series with R1
So the two currents should be equal
The current of R2 and R3 = I2 + I3 = 3 + 2 = 5
So I1 = 5
Then I1: I2: I3 = 5:3:2

Three resistors are connected in parallel, R1 = 4 Ω, R2 = 6 Ω, R3 = 8 Ω. What is the current ratio I1: I2: I3 through these three resistors?

Because of parallel connection, U1 = U2 = U3, so I1: I2: I3 = (U1 / R1): (U2 / r2): (U3 / R3) = 6:4:3

Given that the general term formula of sequence {an} is an = (n + 2) (78) n, then when an gets the maximum value, n is equal to______ ．

From an + 1An = 78 (n + 3) n + 2 = 7n + 218n + 16 = 78 (1 + 1n + 2) ≥ 1, the solution is n ≤ 5, and 1n + 2 monotonically decreases. When n = 5 or 6, an gets the maximum. So the answer is: 5 or 6

Not because I don't want to, but because I can't speak English
Not because I don't want to, but because I can't

It's not I don't want do it but I can't do it

How many dimes is 120 yuan

240

If we use the dichotomy method to find the root of the spherical equation x ^ 3-x-3 = 0 in the interval (1,2), and take the midpoint of the interval as x0 = 1.5, then the next interval with roots is x ^ 3-x-3 = 0

（1.5,2）
f（2）＞0,f（1.5）＜0

How to write the English words of shoes

Shoes
But we usually use the plural shoes
Because there are two shoes

The sum of the first n terms of {an} is s, and Sn = 1 / 8 (an + 2) & # 178

sn=(1/8)(an+2)²
S(n-1)=(1/8)[a(n-1)+2]²
an=Sn-S(n-1)=(1/8){(an+2)²-[a(n-1)+2]²}
=(1/8)[(an+a(n-1)+4][an-a(n-1)]
8an=an²-a(n-1)²+4an-4a(n-1)
[an+a(n-1)][an-a(n-1)]-4[an+a(n-1)]=0
Divide both sides by an + a (n-1)
an-a(n-1)=4
So {an} is an arithmetic sequence with tolerance 4

How to prove that ∫ L (xdx + YDY) (x ^ 2 + y ^ 2) has nothing to do with path?

Suppose the starting point and the ending point, as well as an integral path,
A straight line is used to connect the starting point and the ending point to form a loop with the integral path,
It is proved that the loop integral is 0, so the integral of any path is equal to the integral of negative line

Calculate with appropriate method: (- 5) times 3 and 1 / 3 + 2 times 3 and 1 / 3 + (- 6) times 3 and 1 / 3

Original form
=(- 5 + 2-6) × 3 and 1 / 3
=(- 9) × 10 / 3
=-3×10
=-30