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Can the square of matrix (a + b) also be directly calculated by the square formula, which is equal to a + 2Ab + B, and the cube or something
No, not even cubic
As shown in the picture, if not clear, please ask. Please evaluate in time
The matrix A = Cos2 a Cos2 B Cos2 R sin2 a sin2 B sin2 R 1 2 means square. How can this matrix be equal to
It's equal to 0. I'm really 2 when I didn't ask
Matrix A=
cos²a cos²b cos²r
sin²a sin²b sin²r
1 1 1
The value of determinant of matrix A = 0
The matrix cannot be evaluated!
（2+4+6… +100）-（1+3+5… 99) how to do it
（2+4+6… +100) = (2 + 100) X50 divided by 2 = 2550 sum of head and tail multiplied by the number divided by 2 1 + 2 +. + 99
The resultant impulse should be calculated according to the principle of vector combination
It's better to have examples and analyze them
In general, you are not allowed to calculate the combined impulse. After analyzing the force on an object, each force has its corresponding impulse (because there is time accumulation). First, calculate the impulse of each force, and then use the parallelogram rule
A train moves in a straight line with uniform acceleration on a straight track. The length of the train is known to be L,
A train departs from a station and moves in a straight line with uniform acceleration on a straight track. It is known that the length of the train is L. when the locomotive passes a road sign, the speed is V1, and when the tail passes the road sign, the speed is v2. How much is the speed v when the middle point of the train passes the road sign?
V = V1 ^ 2 + V2 ^ 2 radical
Because of the relationship between the velocity and displacement of uniform velocity linear motion, VT ^ 2-v0 ^ 2 = 2As
So V2 ^ 2-V ^ 2 = 2A * (s / 2)
You can get the answer by subtracting V ^ 2-v1 ^ 2 = 2A (s / 2)
Find the limit: LIM (x ^ 2 * sinx-2x ^ 3) / (x ^ 3 + 2x ^ 4) when x tends to 0
lim(x→0) (x^2*sinx-2x^3)/(x^3+2x^4)
=lim(x→0) (sinx-2x)/(x+2x^2) (0/0)
= lim(x→0) (cosx-2)/(1+2x)
=-1
It is known that the general term formula of sequence an is the nth power of an = (n + 1) * (10 / 11). When the number of terms n is, an is the largest
Because each item of the sequence is not negative, then an + 1 - an > 0 = > an + 1 / an > 1 = > [(n + 2) * (10 / 11) ^ (n + 1)] / [(n + 1) * (10 / 11) ^ n] > 1 = > [n + 2] / [n + 1] > 11 / 10 = > N 0, n = 9 = > an + 1 - an = 0, A10 = A9, n > 9 = > an + 1 - an < 0, the maximum of the sequence is
I hope I'm still young
I wish I were young?
Using subjunctive mood
I wish I were young
How much is 5 yuan? How much is 20 yuan
50
two
Use "dichotomy" to find the real root of the equation x3-2x-5 = 0 in the interval [2,3], take the midpoint of the interval as x0 = 2.5, then the next interval with roots is______ ．
Let f (x) = x3-2x-5, f (2) = - 1 ＜ 0, f (3) = 16 ＞ 0, f (2.5) = 1258-10 = 458 ＞ 0, the interval of zero point of F (x) is [2,2.5], the interval of root of equation x3-2x-5 = 0 is [2,2.5], so the answer is [2,2.5]
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