![](data:image/svg+xml;utf8,<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" viewBox="0 0 72 71" width="72"></svg>)
Design a calculation 1 * 3 * 5 * 7 *99 and draw the frame Design algorithm to find 1 / (1 * 2) + 1 / (2 * 3) + 1 / (3 * 4) +1 / (99 * 100) value and block diagram~
1- 1/2 +1/3 -1/4.+1/99 -1/100=99/100
Why is the counting variable i = I + 2 in "design an algorithm to calculate the value of 1 * 3 * 5 * 7 * ········································································?
Because the numbers 1, 3, 5 to 99 are odd and the difference between them is 2, the variable i = I + 2 is in line with the meaning of the problem
The diameter of the bottom of a cylindrical pool is 20 meters and the depth is 2 meters. What is the floor area of the pool? How many cubic meters of soil need to be excavated to dig the pool?
How much is the area of ceramic tile paved on its bottom and around? How long is the railing on the edge of the pool?
Floor area:
3.14×（20÷2）²
=3.14×100
=314 square meters
Excavation required:
314 × 2 = 628 M3
Side area = 3.14 × 20 × 2 = 62.8 × 2 = 125.6 M2
Tile area:
314 + 125.6 = 439.6 square meters
Railings required:
3.14 × 20 = 62.8m
If you have any questions, please ask,
How do 12, 13, 7 and 10 count as 24
1:(12 × (13 + 7)) ÷ 102:12 × (13 + 7) ÷ 103:12 × ((13 + 7) ÷ 10)4:(12 × (7 + 13)) ÷ 105:12 × (7 + 13) ÷ 106:12 × ((7 + 13) ÷ 10)7:12 ÷ 10 ×(13 + 7)8:(12 ÷ 10) × (13 + 7)9:12 ÷ (10 ÷ ...
High number encountered a problem: is in the application of definite integral to find the side area of the body of revolution
I don't understand why it is the above formula shown in the figure instead of the following formula. When calculating the volume of a rotating body, it is the area of that section multiplied by DX, but here it is multiplied by the arc differential DS. When DS approaches 0, can't it be replaced by DX?
Of course, it's not the same. The arc differential is very small, and it can't be regarded as a line segment, because the physical meaning of the two is not the same at all. You can understand that a rotating body is made up of countless tiny rings, rather than one line segment. Since it is a small ring, it must be an integral of the circumference, that is, infinitely many circles of different sizes with radius y
Filling in brackets: 87 decimeters = () meters 55 ml = () liters 46 square centimeters = () square decimeters 145 cubic decimeters = () cubic meters 55 ml=（
）Liter
87 decimeters = (87 / 100) meters 55 ml = (11 / 200) liters 46 square centimeters = (23 / 50) square decimeters 145 cubic decimeters = (29 / 200) cubic meters 55 ml = (11 / 200) liters
As shown in the figure, the front view (or the main view) and the side view (or the left view) of an empty geometry are congruent equilateral triangles, and the top view is a circle with a radius of 1, then the total area of the geometry is ()
A. πB. 3πC. 2πD. π+3
Carefully observing the main view and side view of the geometry, we can see that the geometry is a cone. From the image, we can see that the center angle of the cone is 60 ° and the length of the generatrix l of the cone is 2 and the radius is 1. According to the calculation method of the cone surface area formula: S = π RL + π RR = π × 1 × 2 + π × 1 × 1 = 3 π, we choose B
The parabola y = x & # 178; moves two units up and four units to the left to get the parabola y = x & # 178; + BX + C, and find the value of B and C
Parabola y = x & # 178; move up two units, and then move left four units to get parabola y = x & # 178; + BX + C, find the value of B and c y = (x + 4) &# 178; + 2 = x & # 178; + 8x + 18 = X & # 178; + BX + C; ▽ B = 8; C = 18; I'm glad to answer for you, skyhunter 002 will answer for you if there is anything I don't understand
One ton of coarse sand is equal to 0.69 cubic sand. How many tons of coarse sand are there in 13.5 cubic sand
13.5 △ 0.69 ≈ 19.57 tons
(2x + 1) square - (x + 3) square - (x-1) square + 1,
The original formula = (4x & sup2; + 4x + 1) - (X & sup2; + 6x + 9) - (X & sup2; - 2x + 1) + 1
=4x²+4x+1-x²-6x-9-x²+2x-1+1
=2x²-8
RELATED INFORMATIONS
- 1. Design an algorithm to calculate 1 + 3 + 5 + 7 + 9 +. + 49 Is S1, S2 that is not to calculate the number, not to let the arithmetic sequence! How about the first step, how about the second step
- 2. If 1 + X + x2 + X3 = 0, find x + x2 + X3 + +The value of X2000
- 3. Given 1 + X + x ^ 2 + x ^ 3 = 0, find x + x ^ 2 + x ^ 3 + +The value of x ^ 2000 Well Which one? I made it myself the fastest
- 4. Given 2x + 3y-2 = 0, find the value of [(10 ^ 2) ^ x] times [(10 ^ y) ^ 3] - 99
- 5. (1+2+3+4+····+1999+2000+1999+···+2+1)÷2000
- 6. -(2 * 3) 1 / 2 - (3 * 4) 1 / 2 ·· - (1999 * 2000) 1 / 2
- 7. F (x) = asin (π x + a) + bcos (π x + β) + 4, and f (1999) = 3, find f (2000)
- 8. 1÷(2÷3)÷(3÷4)÷(4÷5)÷.÷(1999÷2000)=
- 9. What is the sum of 1 + 2 + 3 + 4 +. 1999 + 2000 + 2001?
- 10. 1+2+3+4+.+1999+2000+2001
- 11. 2x △ 2.3 = 4.56 & nbsp; & nbsp; & nbsp; 7 (x - 1.2) = 2.1 (test) & nbsp; & nbsp; 0.7 (x + 0.9) = 42 & nbsp; & nbsp; & nbsp; & nbsp; 7x + 3 × 1.4x = 0.2 × 56 (X-9) △ 98-x-9) = 4
- 12. Given X4 + X3 + x2 + X + 1 = 0, find the value of X100 + x99 + x98 + x97 + x96
- 13. 1/(x-1)+1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)+...+1/(x-99)(x-100)
- 14. 1951^2-1950^2+1953^2-1952^2+… +2011^2-2010^2
- 15. 1949^2-1950^2+1951^2-1952^2+… +2001^2-2002^2
- 16. 1949+1950+1951+…… +2010/1950+1951+1952+…… +2010 (1949+1950+1951+…… +2010)/(1950+1951+1952+…… +2010).
- 17. Calculation (1-1 / 1949) (1-1 / 1950) (1-1 / 1951) (1 / 2011-1) (1 / 2012-1), it's better to have an explanation,
- 18. 1 * 2:1 + 2 * 3:1 + 3 * 4:1 +. + 96 * 97:1 It's gone when it comes to 96 * 97. There are 1 * 2 as the denominator, 1 as the numerator, and don't make any mistakes. It's mainly about the understanding process,
- 19. Given that K is an integer, it makes the solution of the equation (k-99) x = 111-100x about X an integer. Try to find all k satisfying the above conditions Given that K is an integer, it makes the solution of the equation (k-99) x = 111-100x about X an integer Try to find the value of all k satisfying the above conditions First degree equation of one variable and its solution in junior high school (Volume B) Tonight! Before 7 o'clock!
- 20. (online, etc.) according to the rule of number arrangement in the figure, what is the row and number of 2009? First line 1 Second line 2 3 The third line 4 5 6 The fourth line 7 8 9 10 …… And so on. According to the rule of number arrangement in the figure, what is the row and number of 2009?