General solution of differential equation (2x + e ^ y + 2) DX + e ^ y (x + 2E ^ Y-1) dy = 0 That's all I got

P (x, y) = 2x + e ^ y + 2 Q (x, y) = Xe ^ y + 2E ^ 2y-e ^ ydp / dy = e ^ y = DQ / DX get u (x, y) = {(2x + e ^ y + 2) DX + F (y) = x ^ 2 + Xe ^ y + 2x + F (y) Du / dy = Xe ^ y + 2E ^ 2y-e ^ ydu / dy = [x ^ 2 + Xe ^ y + 2x + F (y)] "(derivation of Y) = Xe ^ y + F" (y) = Xe ^ y + 2E ^ 2y-e ^ YF "(y)..."

It is known that y = - 4sin & sup2; X + 6cosx-6, (- π / 3)=

y=-4sin^2X+6cosX-6（-π/3=

Finding the range of y = 4sin & sup2; X-2

y=4sin²x-2
=2cos2x
[-2,2]

Let a positive number a.b.c.x.y.z. satisfy ax + by = C, BZ + CX = a, cy + AZ = B, then what is a triangle with A.B.C as its side length?

Acute triangle
ax+by=c =>acx+bcy=c²
bz+cx=a =>abz+acx=a²
cy+az=b =>bcy+abz=b²
So y = (B & sup2; + C & sup2; - A & sup2;) / 2BC = cosa > 0
x=(a²+c²-b²)/2ac=cosB>0
z=(a²+b²-c²)/2ab=cosC>0
A. B and C are all acute angles

Least common multiple of 45 and 72

"952265195" Hello, I'm glad to answer for you!
Because 45 = 3 × 3 × 5, 72 = 2 × 2 × 2 × 3 × 3, so
We have to satisfy three 2's, two 3's and one 5's, then
Their least common multiple is 2 × 2 × 2 × 3 × 3 × 5 = 360

The formula of converting tons into square meters
106G double gummed paper, 889mm in size and 4.123 tons in quantity;
How much is the ton converted into square meter?
What's the formula?

889 = 10000 * 106 / 1000000, so 1 square meter = 10000 * 106 / 1000000 * 889 ton, so 4.123 ton = 4.123 * 1000000 * 889 / 10000 * 106 = 34.578745283

Find the Taylor formula of order n for the following functions at the specified point
1.f(x)=x^4+4,x0=1
2.f(x)=x^2-3x+1,x0=0
3.f(x)=1/x,x0=1
4.f(x)=xe^x,x0=0

Just substitute f (x) = f (x0) + F '(x0) (x-xo) +. + FN (XO) (x-xo) n / N! The first is the n-th derivative of F (x), and the second is the n-th power

Substances can be classified according to their composition or properties. In the following material classifications, only ()
A. Na2SO4 is sodium salt, sulfate and normal salt. B. HCl is monobasic acid, strong acid and volatile acid. C. Fe2O3 is metal oxide, the highest valence oxide and basic oxide. D. Ca (OH) 2 is binary base, slightly soluble base and strong base

A. Na2SO4 is a sodium salt, a sulfate and a normal salt, which is classified according to its composition, so a is correct; B and HCl are monobasic acids, which are classified according to their composition, but strong acids and volatile acids, which are classified according to their properties, so B is wrong; C and Fe2O3 are metal oxides, which are classified according to their composition

How to judge the direction of resultant force? It is the same as the direction of acceleration, so we use the formula F = ma. For example, f-f * cos30 = ma. I always write F and f * cos30 in reverse,

First of all, we should judge the motion state of an object under the external force. If the speed increases continuously, the acceleration a > 0, according to a = f / M = (F1-F2) / m, so we need to use the larger component force to subtract the smaller component force, so as to ensure the acceleration a > 0, that is, use the force in the same direction as the speed to reduce the force in the opposite direction
If the velocity decreases continuously, the acceleration a will decrease

Log2 is the logarithm of base 256

log2^256
2^x=256
x=8

General solution of differential equation (2x + e ^ y + 2) DX + e ^ y (x + 2E ^ Y-1) dy = 0 That's all I got