Math problem (2x ^ 3-x ^ 2 + 5x-3): (X-2) (- x ^ 4 + 3x ^ 2-2x + 1): (x + 1) help me solve these two problems (mainly tell me how to do this kind of problems) thank you!

I don't understand your question very well. Sorry, I can't help you

The equation (1) 4 (x-1) + 5 = 3 (x + 2); (2) 2x + 13-5x-16 = 1

(1) From the original equation, we can get 4x-4 + 5 = 3x + 6, that is 4x + 1 = 3x + 6, transfer and merge the similar terms, we can get x = 5; (2) remove the denominator, we can get 2 (2x + 1) - (5x-1) = 6, remove the brackets, we can get 4x + 2-5x + 1 = 6, that is - x = 3, and change the coefficient of the unknown number to 1, we can get x = - 3

Solve the following equation and check (calculation). (1): 0.9x-0.3 = 5.1 (2): 3x-0.3 = 1.5
eleven

0.9X-0.3=5.1
0.9X=5.1+0.3
0.9X=5.4
X=5.4/0.9=54/9=6
checking calculation:
Left = 0.9 * 6-0.3 = 5.4-0.3 = 5.1 = right;
3X-0.3=1.5
3X=1.5+0.3
3X=1.8
X=1.8/3
X=0.6
checking calculation:
Left = 3 * 0.6-0.3 = 1.8-0.3 = 1.5 = right;

As shown in the figure, it is known that ad is the angular bisector of △ ABC, CE is the height of △ ABC, ∠ BAC = 60 ° and ∠ BCE = 40 ° to find the degree of ∠ ADB

∵ ad is the angular bisector of △ ABC, ∵ BAC = 60 °, ∵ DAC = ∵ bad = 30 °, ∵ CE is the height of △ ABC, ∵ BCE = 40 °, ∵ B = 50 °, ∵ ADB = 180 ° - ∵ B - ∵ bad = 180 ° - 30 ° - 50 ° = 100 °

Can you solve the following problems by using the equation method you have learned? In order to further alleviate traffic congestion, Wuxi City decided to build a light rail from the city center to the airport. In order to complete the project three months ahead of schedule, the original work efficiency needs to be increased by 12%. How many months will it take to complete the project?

Suppose the original plan takes x months to complete the project. According to the meaning of the question, we can get: (1 + 12%) · 1 x = 1 x − 3 solution, x = 28 & nbsp; after testing, x = 28 is the solution of the original equation. Answer: the original plan takes 28 months to complete the project

The distance from the point with abscissa equal to 4 on the ellipse X & # 178 / 25 + Y & # 178 / 16 = 1 to the right focus is

X & # 178 / 25 + Y & # 178 / 16 = 1, abscissa equals 4
The right focus is (3,0)
If x = 4, then
y²=144/25
The distance to the right focus is
√[(4-3)²+y²]=√(1+144/25)=13/5

As shown in the figure, △ ABC is an equilateral triangle, points D and E are on AB and AC respectively, and F is the intersection of be and CD. It is known that ∠ BFC = 120 °. Verification: ad = CE

It is proved that: ∵ - BFC = 120 °, ∵ - ECF = ∵ BFC - ∵ CEB = 120 ° - ∵ ABC is equilateral triangle, ∵ - EBC = 180 ° - 60 ° - ∵ CEB = 120 ° - CEB, ∵ - ECF = ∵ EBC, that is, ? - DCA = ∵ EBC, and ∵ ABC is equilateral triangle, ∵ - CAD = ? BCE = 60 °, AC = CB ≌ △ ACD ≌

The complex Z satisfies W + 4I = 2 + IW, z = 10 / W + | W-3 |, and finds the Real Coefficient Quadratic Equation with Z as root
2. (Z + 1-I) (Z + 1 + I) = 4, find | Z | max

w + 4i = 2 + iw => (1-i)w = 2 - 4i => 2w = 2*(1-2i)(1+i)
=> w = (1-2i)(1+i) = 3 - i
So z = 10 / (3-I) + | 3 - I - 3 | = (3 + I) + 1 = 4 + I
The other root of the real coefficient equation with Z as root must be in the form of a - I, so the sum of the two roots must be a real number
Another two products are (4 + I) (A-I) = 4A + 1 + (A-4) I is a real number, so a = 4
So the quadratic equation of one variable is x ^ 2 - 8x + 17 = 0

Given f (x) = log2 x, find the value of F (8)
I'm not interested in functions. Please help me

f(8)=log2 8=3log2 2=3

The circumference of a rectangle is 20 cm, its length is a cm and its width is B cm. (1) which of the above are constants and which are variables? (2)
The circumference of the rectangle is 20cm, its length is a cm and its width is B cm
(1) Which of the above are constants and which are variables?
(2) How to express B with the formula containing a?

Perimeter is length, length and width are variables

Math problem (2x ^ 3-x ^ 2 + 5x-3): (X-2) (- x ^ 4 + 3x ^ 2-2x + 1): (x + 1) help me solve these two problems (mainly tell me how to do this kind of problems) thank you!