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Given that the function FX satisfies 2fx-f1 / x = 3 / X2, then the minimum value of FX is?
2fx-f1 / x = 3 / X2 (1); 2F (1 / x) - f (x) = 3x & # 178; (2) (1) × 2 + (2): 3f (x) = 6 / X & # 178; + 3x & # 178;; f (x) = 2 / X & # 178; + X & # 178; ≥ 2 √ 2 / X & # 178; × X & # 178; = 2 √ 2; so the minimum value of F (x) is 2 √ 2. Hello, I'm glad to answer for you, skyhunter 002 will answer your questions
Given the function FX = x2 + 2x + a - when a = 1 / 2, find the solution set 2 of the inequality FX > 1. If FX > 0 is constant for any x ∈ [1 + ∞), find the value range of real number a
If the function y = f (x) is differentiable on R and satisfies the inequality XF ′ (x) + F (x) > 0, then the following inequality must be true ()
A. af（a）＞bf（b）B. af（b）＞bf（a）C. af（a）＜bf（b）D. af（b）＜bf（a）
Let g (x) = XF (x), then G ′ (x) = XF ′ (x) + F (x) > 0, the function g (x) increases monotonically on R. ∵ a > b, ∵ g (a) > G (b), ∵ AF (a) > BF (b). Therefore, a
If the solution of the equation 4x + 2m = 0 about X is also a solution of the inequality system, the value range of M can be obtained
1-X
----- - 》 X-2
two
2 (x-3) greater than or equal to X-8
Inequality
-5 / 6 to 1
All the formulas in this chapter of electric power. Like what is the ratio of resistance equal to
Voltage ratio equal to what, resistance ratio, rated voltage, actual voltage, rated current, actual current, rated power, actual power
What I know:
1kw.h=3600000J
I=U/R
P=W/T
P=UI
Q = I RT (q = u / R in series, q = I r in parallel)
P real = (U real / u amount) and then multiplied by P amount
(Note: square is square)
The uniform slender straight bar AB has a mass of M and a length of L, and can rotate around the horizontal fixed axis A in the vertical plane. When the bar is in the position shown in the figure, its angular velocity is, then the instantaneous velocity is
The mass and length of the homogeneous slender straight bar AB are m and l, and it can rotate around the horizontal fixed axis A in the vertical plane. When the bar is in the position shown in the figure, its angular velocity is w, then the kinetic energy t of the instantaneous bar AB is 0=___________ ．
Picture Baidu Hi for you
Moment of inertia of rod J = m * L ^ 2 / 3
The kinetic energy of the rod is t = J * ω ^ 2 / 2 = m * (ω L) ^ 2 / 6
How many kilograms is seven fifths of a ton?
1 ton = 1000 kg
(7 / 50) * 1000 = 140 kg
20. The spring scale hangs a piece of iron weighing 19.6n and slowly immerses it in the beaker filled with water. The indication of the spring scale is 9.8N. The buoyancy of the iron in the water is (). The mass of the overflow water from the beaker is () kg, and the volume of the overflow water is () m3
Come on! This is the most basic topic in buoyancy
Answer: 9.8 Niu 10.001, go down and have a good look at the textbook
This experiment is the exploration of Archimedes principle experiment in the textbook. Be familiar with it!
If the perimeter of the large shape is 20, the functional relationship between the area s of the rectangle and the length x of one side is --- where the value range of the independent variable x is--------
If the perimeter is 20, the sum of the two sides is 10, one side is x, and the other side is 10-x (0
As shown in the figure, two blocks a and B with mass ma and MB are stacked together. If they slide uniformly along the inclined plane fixed on the horizontal ground with angle α, then ()
A. There is no friction between a and B. B. there is friction between a and B, and the friction between a and B does positive work for B. the dynamic friction coefficient between C. B and the inclined plane μ = Tan α D. the friction direction between B and the inclined plane is downward along the inclined plane
A. According to Newton's third law, the static friction force on B is magsin α, parallel to the inclined plane downward, so the friction force of a on B does positive work on B, so a is wrong and B is correct; C, D, taking the whole as the research object, if the sliding friction force on B is f, then there are: F=（ Ma + MB) GSIN α = μ (MA + MB) GCOS α, so μ = Tan α; according to Newton's third law, the direction of friction force between B and inclined plane is downward along the inclined plane; so C is correct, D is correct, so BCD is selected
RELATED INFORMATIONS
- 1. If the solution of the equation 1 + 2-x of x = x-4 = 2m is also a solution of the inequality system, can you find the value range of M?
- 2. Solving inequality (X & # 178; - 2 (x) - 2) ≥ 1 and (2x + 1) - (X-2) < 4 brackets is the process of finding absolute value
- 3. Factorization square difference formula - x ^ 2 + y ^ 2
- 4. If y + 3 = √ 2x-5 + √ 10-4x, then the value of 2XY is ()
- 5. Given that X and y satisfy x ^ 2 + y ^ 2 = 2x + Y-5 / 4, find the value of x ^ 2-2xy-y ^ 2 Encountered problems, please give me more advice
- 6. Given that a is a root of the equation x-x-1 = 0, find the value of cube-2a + 2007 of A
- 7. Let a and B be the two real roots of the equation x2 + x-2009 = 0, then the value of A2 + 2A + B is () A. 2006B. 2007C. 2008D. 2009
- 8. The equation x ^ 2 + 2x + a = 0 of X has a solution in the interval [- 3,1]. Find the value range of real number a
- 9. Given that x = 1 is the solution of equation 3ax-1 = A-1, find the value of A
- 10. The constant of the quadratic equation (A-3) x-3ax + 2A = 4 is 4. The number of quadratic terms and the coefficient of the first term are obtained
- 11. The solution set of inequality (2a-b) x + (- a-5b) > 0 about X is x < 73, then the solution set of inequality (3b-5a) x < 17a + B about X is x < 73______ ；
- 12. If a is less than 0, then the solution set of the inequality system X is greater than - 2A and X is greater than - 3a is
- 13. Given that the function f [x] = x square + [A-3] x-3a... A is a constant, if A5, the solution of inequality negative f [x] is greater than 0
- 14. The inequality x ^ 2 + 2aX + a > 0 holds for X ∈ (1,2] to find the range of A x∈[1,2)
- 15. If the equation x 2 - ax + a 2 - 4 = 0 about X has two positive real roots, find the value range of A
- 16. Given the square of equation AX - X-5 = 0, one is greater than - 1, the other is less than - 1, find the value range of real number a
- 17. If the function f (x) = 2ax2-x-1 has exactly one zero point in (0,1), then the value range of a is () A. （1，+∞）B. （-∞，-1）C. （-1，1）D. [0，1）
- 18. Given that f (x) = x square + ax-a, if x belongs to [- 2,2], f (x) is equal to or greater than 0, the value range of a is obtained
- 19. It is a little difficult: given the ax power of the function f (x) = (x ^ - X-1 / a) e, (a is not equal to 0.1, find the tangent equation of the curve y = f (x) at the point a (0, f (0)). 2, when a = 3, find the minimum value of F (x)
- 20. Mathematics problem known y = x square + ax + B, when x = 1, y = 2; when x = - 1, y = 4, when x = 1 / 2, y value