(X-2500)*[8+(2900-X)/50*4]=5000

(X-2500)*[8+(2900-X)/50*4]=5000

Let a = x-2500
A*[8-A/50*4+400/50*4]=5000
A*[40-4A/50]=5000
A*[500-A]=62500
-A^2+500A-62500=0
-(-250 + A)^2=0
A=250
So x = 2750

Solution equation (4 * (2900-x) / 50 + 8) (x-2500) = 5000

(4* (2900-X) +400 )(X-2500)=250000

(x-2500) (x-2900 of 50 times 4 + 8) = 5000

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How to prove Lim [f (x + H) + F (X-H) - 2F (x)] = f "(x) where h tends to 0

lim[f(x+h)+f(x-h)-2f(x)]
=lim(f(x+h)-f(x)-{(f(x)-f(x-h)}
=lim{f'(x)-f'(x-h)}
=f"(x)
Next, there's another H!

The x power of a is equal to 12, and the Y power of a is equal to 2. Find the value of x minus 2Y power of A

a^(x-2y)=a^x/(a^y*a^y)=12/(2*2)=3

What color shirt do you want

which colour of the shirt do you want

How many square kilometers is an acre equal to

1 square kilometer = 1000 * 1000 = 1000000 square meters
1 mu = 666.666... M2
1 hectare = 15 mu
1000000/666.66＝1500.02
So,
1 square kilometer = 1500 mu = 100 ha
1 mu = 1 / 1500 square kilometers
Hope to help you

It is known that a and B belong to R, a > b > e, (E is the base of natural logarithm), and it is proved that the power a of B is greater than the power B of A

In（b^a）=aIn b
In（a^b) =bIn a
The second formula except the first one is: in [(a ^ b) - (b ^ a)] = (B / a) in (a-b)
Because a > b > e, b-a0
So in [(a ^ b) - (b ^ a)]

Can you tell me how to get to the bus stop?

could you tell me how to go to the bus station

The square difference of two consecutive odd numbers must be an odd number. Is that right? Prove your idea

Let the two consecutive odd numbers be 2n + 1,2n-1,
Then (2n + 1) & # 178; - (2n-1) & # 178;
=4n×2
=8n,
The square difference of two consecutive odd numbers must be a multiple of 8, not an odd number