There are 44 students in Grade 5 (3) class of sunshine primary school, among which boys account for 5 / 11 of the total number of students in the class, and the number of girls in class 5 (2) is 7 more than that of girls in class 5 (3) So how many girls are there in no (2) class?

There are 44 students in Grade 5 (3) class of sunshine primary school, among which boys account for 5 / 11 of the total number of students in the class, and the number of girls in class 5 (2) is 7 more than that of girls in class 5 (3) So how many girls are there in no (2) class?


Hello:
44×(1-5/11)+7
=44×6/11+7
=24+7
=31 (person)
A: there are 31 girls in class 5 (2)



The highway from Lishan town to the provincial capital is 189 kilometers long, passing through the county. The county is 54 kilometers away from Lishan town. A bus leaves Lishan town at 8:30 in the morning and arrives at the county at 9:15. It stops for 15 minutes and then leaves for the provincial capital. It can arrive at 11:00 in the afternoon. Another bus goes straight from the provincial capital path to Lishan town at 9:00 in the morning. It runs 60 kilometers per hour. When the two cars meet, the provincial capital goes to Lishan town The mountain town bus is running______ Minutes


9: 15 + 15 minutes = 9:30, 11:00-9:30 = 1.5 hours, 30 minutes = 0.5 hours, (189-54) △ 1.5, = 135 △ 1.5, = 90 (km), 189-54-60 × 0.5, = 189-54-30, = 135-30, = 105 (km), 105 △ 60 + 90, = 105 △ 150, = 0.7 (H) = 42 (min)



How long do you drink glucose before 1000 meter long run?


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Is there any way to do the seventh grade Chinese reading problem?


1. First of all, read through the full text to understand the main idea of the full text
2. Look at the problem, analyze the focus of the question, read the full text with the question and try to solve the problem
3. For the unsolved questions, the paper analyzes the context and the main idea of the whole text, and finally answers the general questions



What is the least common multiple of 20 ` 15 and 30


60, right
Reason 1: calculated. 2 * 2 * 3 * 5 = 60
Reason 2: intuition
Reason 3: there are so many people supporting me, of course, 60



The solution ratio is 12:6 = x: 20 and 0.8:3 and 3 / 4 = x: 0.75


X = 40 x = 4 / 25



If the rational number a B satisfies A-1 + b-2011 = 0, then the power of a of B = --


|a-1|=0
a=1
|b-2011|=0
b=2011
b^a=2011^1=2011
A power of B = 2011



If the sequence {an} is known to be both arithmetic and proportional, then the sum of the first n terms of the sequence is ()
A. 0B. nC. na1D. a1n


If the sequence {an} is both an arithmetic sequence and a proportional sequence, then the sequence is a non-zero constant sequence, that is, A1 = A2 = A3 = An, then the sum of the first n terms of the sequence is a1 + A2 + a3 + +An = Na1, so C



It is known that the function f (x) = X2 (ax-3) defined on R, where a is a constant. (1) if a = 1, find the tangent equation of the image of F (x) at points (1, - 2); (2) if x = 1 is an extreme point of function f (x), find the value of real number a; (3) if f (x) is an increasing function in the interval (- 1,0), find the value range of real number a


(1) When a = 1, f (x) = x3-3x2, then f ′ (x) = 3x2-6x = 3x (X-2), then k = f ′ (1) = - 3, then the tangent equation is y + 2 = - 3 (x-1), that is, 3x + Y-1 = 0; (2) f (x) = ax3-3x2, we get that f ′ (x) = 3ax2-6x = 3x (AX-2), ∵ x = 1 is an extreme point of F (x), ∵ f ′ (1) = 0, that is, 3 (A-2) = 0, ∵ a = 2; (3) when a = 0, f (x) = - 3x2 is in the interval (- 1) When a ≠ 0, f ′ (x) = 3ax (x-2a), Let f ′ (x) = 0, then X1 = 0, X2 = 2A, when a > 0, for any x ∈ (- 1,0), f ′ (x) > 0, then a > 0; when a < 0, when x ∈ (2a,0), f ′ (x) > 0, then 2A ≤ - 1, ■ - 2 ≤ a < 0, then a ≥ - 2 meets the requirements



Page 18, question 18
In the tug of war competition, Party A is on the right and Party B is on the left. The balance position is 0. If Party A pulls 1cm to the right, mark as + 1cm, then Party B pulls 1cm to the left, mark as - 1cm. The following table records the process of a contest between the two sides and answers the following two questions. (figure, in words) (1) Party A + 10, ask Party B how much. (2) Party B counts as - 8, ask Party A how much. (3) 8 for Party A and how much for Party B. (4) Party B counts - 6, ask Party A how much. Is the final position left or right? Which side will win?


(1) Party B at - 10
(2) Party A at + 8
(3) Party B is counted as - 8
(4) Party A is counted as + 8
Party A won