How to solve the equation 48x = 60 (x-4 / 5)

48x=60（x-4/5)
48x=60x-60*4/5
12x-48=0
x=4

How to solve the equation x-40-x-60 = 4 + 5

x/120=9
x=1080
He died of cold

How to calculate 4.8 times 0.25?
List the formula in a way

Because: 0.25 = 1 / 4
So:
4.8×0.25
=4.8÷4
=1.2

As shown in the figure, the overlapping area of the two parallelograms is equivalent to 1 / 12 of the area of the large parallelogram and 1 / 6 of the area of the small parallelogram
As shown in the figure, the overlapping area of two parallelograms is equivalent to 1 / 12 of the area of the large parallelogram and 1 / 6 of the area of the small parallelogram. What is the area ratio of the large parallelogram to the small parallelogram?

The area of the overlapping part of the two parallelograms is equal to 1 / 8 of the area of the large parallelogram
From this sentence, we can see that he divided the large parallelogram into eight parts on average, and the area of the overlapping part accounted for one of them. We took the area of the large parallelogram as eight, It is equivalent to one sixth of the area of the small parallelogram. From this sentence, we can see that he divided the small parallelogram into six parts on average, and the area of the overlapping part takes one of them. We regard the area of the small parallelogram as 6
The ratio is 8:6 = 4:3

Finding the vertex coordinates of square-2-1 of quadratic function y = 1 / 2x by vertex coordinate sum matching method

Preparation method:
y=½x²-2x-1
＝½(x²-4x)-1
=½(x²-4x+4-4)-1
=½[(x-2)²-4]-1
=½(x-2)²-2-1
=½(x-2)²-3
The vertex coordinates of the parabola are (2, - 3)
Formula method:
-b/(2a)
=-(-2)/(2×½)
=2/1
=2
(4ac-b²)/(4a)
=[4×½×(-1)-(-2)²]/(4×½)
=(-2-4)/2
=-6/2
=-3
The vertex coordinates of the parabola are (2, - 3)

If x square - (M-3) x + 9 is a complete square, then M=

x²-(m-3)x+9
=(x±3)²
=x²±6x+9
So, M-3 = ± 6
So, M = 9 or M = - 3

The area of a right triangle is 12 square centimeters, and one right side is 3 centimeters. What is the area of a circle drawn with the other right side as the diameter?

12 × 2 / 3 = 8 (CM) 3.14 × (8 / 2) 2 = 3.14 × 16 = 50.24 (square cm) a: the area of this circle is 50.24 square cm

P is the point on the right branch of hyperbola x2a2 − y2b2 = 1 (a > 0, b > 0), F1 and F2 are the left and right focal points of hyperbola respectively, and the focal length is 2c, then the abscissa of the center of the inscribed circle of △ pf1f2 is ()
A. -aB. aC. -cD. c

∵ point P is a point on the right branch of hyperbola, | Pf1 | - | PF2 | = 2A according to the definition of hyperbola. If the projection of the center of the inscribed circle of triangle pf1f2 on the horizontal axis is a (x, 0), this point is also the tangent point of the inscribed circle and the horizontal axis. Let B and C be the tangent points of the inscribed circle and Pf1 and PF2 respectively F2 = af1-f2a = (c + x) - (C-X) = 2x = 2aX = a, so the abscissa of the center of the inscribed circle is a

How to read the sign of partial derivative?

Read: dround

3 / 8 of a bridge has been repaired. A. the repaired part is regarded as unit "1". B. the unmodified part is regarded as unit "1"
c. The total length is unit '1'

How to solve the equation 48x = 60 (x-4 / 5)