Please write a logical expression: X is greater than 10 and Y is not greater than 10, at least one of which holds. (C language)

Please write a logical expression: X is greater than 10 and Y is not greater than 10, at least one of which holds. (C language)

(x>10||y

The value of expression 5 ^ 2 in C language is equal to
I don't know what ^ means,

#include "math.h"
It's necessary,
The usage of power is pow (number, power)

Is a = 2 an expression in C language? If so, is the value of this expression equal to 2

Yes. It's an assignment statement. If the value of the expression is 2 plus a semicolon, it's a statement

（4.5-x）X7=17.

4.5-X=17.5/7
4.5-x=2.5
4.5-2.5=x
A: x = 2

Sequence 1, m, M & # 178 The sum of the first n terms of is equal to ()
A. (1-m ^ n) / (1-m) B. (1-m ^ n-1) / (1-m) C. (1-m ^ n + 1) / (1-m) d
Why is the answer D? This is an equal ratio sequence, the common ratio is m, A1 = 1, we can get that SN is the a option

It doesn't hold when m = 1

That's right. Add another point. - 2, negative half, 5.2, 0, negative two-thirds, one sixth, negative five-thirds, 2005, negative zero point three. There's something else to add
The math teacher answered, the set of positive numbers, the set of negative fractions and the set of non negative rational numbers

Set of positive numbers = {5.2, 6 / 1, 2005}
Negative fraction set = {negative two thirds, negative five thirds, negative zero three.}
Set of nonnegative rational numbers = {5.2,0, 6 / 1, 2005,}

(3a + 2) x + (1-4a) y + 8 = 0 and (5a-2) x + (a + 4) Y-7 = 0 how to get (3a + 2) (5a-2) + (1-4a) (a + 4) = 0 by finding a vertically

If the product of the slopes of two straight lines is - 1, then [- (3a + 2) / (1-4a)] × [- (5a-2) / (a + 4) = - 1, then (3a + 2) (5a-2) = - (1-4a) (a + 4) (3a + 2) (5a-2) + (1-4a) (a + 4) = 0

How to put the nine numbers 1-9 into the 3 * 3 lattice? No matter how they are added, they are equal to 15?

6 1 8 7 5 3 2 9 4 1-9 the middle number is put in the middle grid, the others are a pair of numbers, the two numbers add up to 10, 1 + 9; 2 + 8; 3 + 7; 4 + 6, and then you can make it

X-y-2z = 10; y-3z = - 4; 3x-y + 5Z = 21; solve the ternary linear equations

Substituting x = y + 2Z into 3x-y + 5Z = 21
Formula 3: 5Y + 11z = 21
2,3 simultaneous. Solve ZY and substitute it into 1

1999÷199919992000．

1999÷199919992000，=1999÷1999×2000+19992000，=1999×20001999×(2000+1)，=20002001．