Given that X and y satisfy the cubic power of y = the arithmetic square root of the square of X-9 + the arithmetic square root of the square of 9-x + 6 divided by x-3, try to judge whether there is a square root of X + y

Given that X and y satisfy the cubic power of y = the arithmetic square root of the square of X-9 + the arithmetic square root of the square of 9-x + 6 divided by x-3, try to judge whether there is a square root of X + y

x²-9>=0
9-x²>=0
x-3≠0
∴x=-3
Then y & # 179; = 0 + 0 + 6 / (- 3-3) = - 1
y=-1
There is no square root for x + y = - 4

If x and y are real numbers and the square roots of lx-2l and Y-3 are opposite to each other, find the square root of the algebraic formula 6xy + 64

The square roots of L, X-2, l and Y-3 are opposite to each other
L X-2 L and Y-3 = 0
x=2
y=3
(6xy+64)^2=10000

How to write a program with Java, input the number n from the keyboard, calculate and output the result of 1! + 2!... + n
In addition, the method of how to write factorial is attached,

import java.util.Scanner ;
public class A{
//The following method is to factorize a single number and return
public static int jieCheng(int n){
int sum=1;
for(int i=1;i

Java operators
What are the Java operators and their usage

Java operators can be divided into four categories: arithmetic operators, relational operators, logical operators and bitwise operators. 1. Arithmetic operators Java arithmetic operators are divided into unary operators and binary operators. Unary operators have only one operand; binary operators have two operands, the operator is located between the two operands

Given a-b-3ab = 0, find the value of (a-b-6ab) of (2a-2b + 3AB)

Hello, old Wutong in alley.
∵a-b-3ab=0
∴a-b=3ab
∴(a-b-6ab)/(2a-2b+3ab)
=[(a-b)-6ab)]/[2(a-b)+3ab]
=[3ab-6ab]/[6ab+3ab]
=(-3ab)/9ab
=-1/3

(x________ )(_________ -3y)=x^2-9y^2

（x+3y）(x-3y)

How to calculate (the square of X + 5x + 6) / (x + 2)

How to calculate (the square of X + 5x + 6) / (x + 2)
The results are as follows
(x^2+5x+6)/(x+2)
==(x+2)(x+3)/(x+2)
==x+3

We know that a = 3A's Square - 2b's Square, B = A's square + 6B's Square, (1) a's square + B's Square

A＋B＝3a²-2b²+a²+6b²
=4a²+4b²
=4(a²+b²)
So we can get: A & # 178; + B & # 178; = (a + + b) / 4

3 times (1 / 5 X-2) = 9 (solving the equation)

3 times (1 / 5 X-2) = 9
1 / 5 X-2 = 9 / 3
1 / 5 x = 3 + 2
X = 1 / 5
x=25

Solution equation: 0.4 x + 1-0.7 x + 1 = 10.3 X-1 = 0.4 x + 2 + 3 5
solve equations:
0.4 x + 1-0.7 x + 1 = 1
0.3 X-1 = 0.4 x + 2 + 3 5

The original equation can be reduced to: (10x + 10) / 4 - (5x + 10) / 7 = 1, remove denominator: 7 (10x + 10) - 4 (5x + 10) = 1, remove bracket: 70X + 70-20x + 40 = 1, shift term: 70x-20x = 1-70-40, merge similar term: 50x = - 109, coefficient 1: x = - 5 / 109. The original equation can be reduced to: (10x-10) / 3 = (10x + 20) / 4 + 5 / 3, remove denominator: 4 (10x - 10) = 3 (10