How many kilos is 270g equivalent to 12kg in 16KG

How many kilos is 270g equivalent to 12kg in 16KG

73 kg

A student's car is driving on the highway at the speed of 120km / h
A classmate's car is driving on the highway at the speed of 120km / h. he counts his pulse from the first milestone. When the car passes the seventh milestone, he counts the 216 pulse. How many times does his pulse beat per minute?

72 times. If the speed is 120km / h, 2km in one minute, and 6km in seven milestones. Therefore, walking for 3 minutes, i.e. 216 divided by 3 = 72 times / min

If A.B.C are all integers and ABC = 21, the maximum value of a + B + C is? A + B + C and the minimum value of a + B + C is?

Maximum a + B + C = 21 + 1 + 1 = 24
Minimum a + B + C = - 21-1 + 1 = - 21

A car starts at 7:00, arrives at the destination at 4:00 p.m., and has lunch at 12:00 p.m. to 1:00 p.m?

(9-1) * 55 = 440km

How to simplify the problem of distribution law? 2.8 divided by three fifths plus (0.52 plus 0.6) =

Is the title wrong?

When the speed of a train is 168 km | now, it is 20% higher than that before the speed increase. What is the speed of this train before the speed increase? (use equation solution)

Set the original x km / h
Then x (1 + 20%) = 168
x=168÷1.2=140
A: it used to be 140 kilometers per hour

What is the number of times of a monomial

The sum of the exponents of all the letters is called the number of times of this monomial

There is a batch of cement on the construction site. After five seventh of the cement is used, 2.3 tons of cement is transported. This is 0.8 tons more than the original cement. How many tons of the original cement are there?
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Urgent! Please help me

Let this batch of cement be x tons, then 5 / 7X + 2.3-x = 0.8, x = 5.25 (tons)
A: it turns out that this batch of cement is 5.25 tons

In the acute triangle ABC, the angle B = 80 degrees, the vertical bisectors of AB and AC intersect at point O, and the degree of & # 131275; BOC is calculated

Is it ∠ a = 80?
Connect to OA
∠BOC=∠A+1/2∠B+1/2∠C
=∠A+1/2(∠B+∠C)
=∠A+1/2(180°-∠A)
=90°+1/2∠A
=130°

There is a square paper with an area of 1 square meter, half of which is cut off in the first time, and the remaining half is cut off in the second time. If so, how many square meters is the remaining paper area after the fifth time?

The fifth time is (12) 5 = 132 square meters. Answer: the fifth time is 132 square meters