If the speed of the bicycle is always a, the speed of the car is always B. If b = a + 1, who will arrive first? Party A and Party B start from a to B at the same time. The way to take this part of the road is to ride a bicycle for the first two-thirds of the distance and take a car for the last one-third of the distance. Party B's way is to ride a bicycle for the first two-thirds of the time and take a car for the last one-third of the time. If the speed of the bicycle is always a and the speed of the car is always b, if B = a + 1, who will arrive first?

If the speed of the bicycle is always a, the speed of the car is always B. If b = a + 1, who will arrive first? Party A and Party B start from a to B at the same time. The way to take this part of the road is to ride a bicycle for the first two-thirds of the distance and take a car for the last one-third of the distance. Party B's way is to ride a bicycle for the first two-thirds of the time and take a car for the last one-third of the time. If the speed of the bicycle is always a and the speed of the car is always b, if B = a + 1, who will arrive first?

Arrive at the same time

2X of 0.3-6x of 0.1-5 = 2

(20x-1)/3-(6x+2)/5=2
100x-5-18x-6=30
82x=41
∴x=1/2

The distance between a and B is 540 km. The passenger and freight cars leave from both places at the same time. When they leave for 4 hours, they are still 15 km apart. It is known that the speed ratio of passenger cars and freight cars is 4:3. How many hours does it take for a passenger car to complete the whole journey?

(540-15) △ 4 = 131.25 (km) - speed and
131.25 ÷ (4 + 3) × 4 = 75 (km) - bus speed
540 △ 75 = 7.2 (hours)
It takes 7.2 hours for the bus to complete the journey

What is the number on the 99th place after the decimal point? What is the number on the 199th place?

5 △ 7 = 0.714285... Six bit one cycle
99 ÷ 6 = 16,3
So the number in the 99th place is the number in the third place, which is 4
199 △ 6 = 33 + 1
So the number in number 99 is the number in number 1, which is 7
Hope to adopt. Thank you!

A and B start from a and B at the same time and run in opposite directions. They meet at 5 o'clock. Car a travels 50 kilometers per hour, while car B travels 40 kilometers per hour. After meeting, car a continues to move forward
A few hours later, car a arrived at place B

40×5÷50
=200÷50
=4 hours

In △ ABC, asinbcosc + csinbcosa = 12b, and a > b, then ∠ B = ()
A. 5 π 6 or π 6B. 2 π 3 or π 3C. π 3D. π 6

In △ ABC, ∵ asinbcosc + csinbcosa = 12b, ∵ from the sine theorem, we get: sinasinbcosc + sincsinbcosa = 12sinb, SINB ≠ 0, ∵ sinacosc + sinccosa = 12, ∵ sin (a + C) = 12, a + B + C = π, ∵ sin (a + C) = sin (π - b) = SINB = 12, a > b, ∵ B = π 6

The speed ratio of the bus to the truck is 7:5. The bus travels 56 kilometers more per hour than the truck. How many hours does the truck travel from place B to place a?

56 ÷ (7-5) = 28 km / h
28 × (7 + 5) × 4 = 1344km
1344 ÷ (28 × 5) = 9.6 hours

If the average of a set of data 3, x, 0, - 1, - 3 is 1, then x is equal to______ ．

If the average number of 3, x, 0, - 1, - 3 is 1, then 15 (3 + X + 0-1-3) = 1, x = 6

The speed ratio is 2:3. A starts 15 minutes earlier than B. when B meets in 1 hour and 45 minutes, a walks 6 kilometers less than B,
The speed of a and B and the distance between a and B

B speed x a speed x * 2 / 3
Class A (x * 2 / 3) * 15 + (x * 2 / 3) * (60 + 45)
B * x * (60 + 45)
105X - [(X*2/3) * 15+(X*2/3) *(60+45)]=6
105X - 80X = 6
X=0.24
X*2/3=0.16
Distance 105x + 80x = 44.4

Calculation: 8 (72 + 1) (74 + 1) (78 + 1) (716 + 1) (732 + 1)

The original formula = (7 + 1) (7 − 1) (72 + 1) 6 · (74 + 1) (716 + 1) (78 + 1) = 16 (72-1) (72 + 1) (74 + 1) (78 + 1) (716 + 1) (732 + 1) = 16 (74-1)) (74 + 1) (78 + 1) (716 + 1) (732 + 1) = 16 (78-1) (78 + 1) (716 + 1) (732 + 1) = 16 (716-1)