11. It is known that y + 1 is proportional to x, and when x = 3, y = 5, the functional relationship between Y and X is obtained, and the value of a when the point (a, - 2) is on the function image is obtained

11. It is known that y + 1 is proportional to x, and when x = 3, y = 5, the functional relationship between Y and X is obtained, and the value of a when the point (a, - 2) is on the function image is obtained

It is known that y + 1 is proportional to X
Let y + 1 = KX, x = 3, y = 5
5+1=3k
k=2
So the functional relationship between Y and X
y+1=2x
When (a, - 2) is on the image
-2+1=2a
a=-1/2

If y = KX is shifted to the left by two unit lengths (0, - 4), then the inequality 2x is obtained

Obviously, if y = KX passes through the origin, then it must pass through (- 2,0) and (0, - 4) after moving left by two unit lengths. Let y = KX + B pass through points (- 2,0) and (0, - 4) after moving left, then k = - 2 and B = - 4
So the inequality 2x

In the plane rectangular coordinate system xoy, two points a and B are on the positive half axis of X axis and Y axis respectively, and ob = OA = 3
Point P is a point on the bisector of the first and third quadrants. If the triangle ABP = 33 / 2, find the coordinates of point P

From the question a (3,0) B (0,3) ‖ AB = 3 √ 2
Let P = (x, x)
∴S=((√2)x-3/(√2))3√2×1/2=33/2
∴x=7,P(7,7)
This is in the first quadrant
If it's in the third quadrant
S=(-(√2)x+3/(√2))3√2×1/2=33/2
∴x=-4,P(-4,-4)
Ψ P (7,7) or (- 4, - 4)

Find the rule: 1,1,1,3,5,9, (), ()

1+1+1=3
1+1+3=5
1+3+5=9
3+5+9=17
5+9+17=21
17, 21 in brackets

Let 1, 2, 3 It is known that the last 13 digits of the product are all exactly 0. May I ask: what is the minimum natural number that appears at the end of multiplication?

Only the multiplication of factor 2 and 5 can get a 0. If the last 13 bits of the product are all exactly 0, then at least 13 factor 2 and 13 factor 5 are needed. There are many factors in factor 2. To get 13 factors, 5, 5, 10, 15, 20, 30, 35, 40, 45, 55 each can get a factor 5, a total of 9, 25, 50 each can get

Like 1.2.3 Such numbers are called natural numbers. Integers have a larger range than natural numbers. What numbers have a larger range than integers
There are a wider range of numbers

Rational numbers are larger than integers, real numbers are larger than rational numbers, and complex numbers are larger than real numbers

Fill in 5, 7, 10, 14, 15, 21, (), ()

20 and 28
5 * 2 = 10, 5 * 3 = 15, so the first blank is 5 * 4 = 20
7 * 2 = 14, 7 * 3 = 21, so the second blank is 7 * 4 = 28

It is proved that the product of four continuous natural numbers plus 1 is the square of a natural number

(n-2)(n-1)n(n+1)+1=(n^2-n-2)(n^2-n)+1
=(n^2-n)^2-2(n^2-n)+1
=(n^2-n-1)^2

Given the function f (x) = x ^ 2 + 1 - ax under the root
The function f (x) = root √ x ^ 2 + 1 - ax is known. Where a > 0, if 2F (1) = f (- 1), the value of a is obtained. It is proved that if and only if a > = 1, the function f (x) is a monotone function in the interval [0, positive infinity]. If the function is an increasing function in the interval 1 to positive infinity, the value range of a is obtained,

f(x)=√(x^2+1) -ax
Any 1 ≤ x1

Forwards I am heavy.Backwards I am not.What am

Forwards I am heavy .Backwards I am not.What am
I'm very heavy in front, but not in the reverse. What am I?
The answer: ton, because it's ton on the front and not on the back