The feeling of doing housework 500 words

The feeling of doing housework 500 words

If someone asked me, "do you like doing housework?" I would tell her with pride, "I like doing housework best." in fact, when I did housework for the first time, I was very unhappy. But now I like it. It was a summer noon. When I was just half eaten, my mother said to me, "from today on, it's up to you to wash the dishes." after that, I went to bed, But I couldn't help it. After eating, I went to the bathroom and put a basin of water into the water. When I was ready to wash, I suddenly saw the oil on the plate. I felt uncomfortable. I reluctantly washed the tableware with detergent. I poured another basin of water and cleaned the tableware again. The tableware was bright. My mood was suddenly happy and I thought, "this time I can be praised.", As expected, I was really praised. My mother went to bed with me and saw that I washed the dishes so clean. She said with a smile, "the sun is coming out from the West today. Isn't it pretty good!" I was very happy and happy. Since then, I love doing housework. My friend, because you are a member of the family, you can do housework too! You will get praise and endless fun

After helping my mother do housework, I can keep a diary of 200 words

How to compare the size relation of ABC in quadratic function

When a ＞ 0, the opening of quadratic function image is upward; when a ＜ 0, the opening of parabola is downward. The larger | a | is, the smaller the opening of quadratic function image is

2489 = 3 7126 = 1 1111 = 0 2222 = 0 0000 = 4 Q: 2899 =?

9038 = 43148 = 26666 = 4, ask 2889 =?... 5 in fact, the principle is that circle 8 has two circles, 9 has only one, and so on

Given that the function f (x) = log2 (x ^ 2 + ax-2a) is an increasing function in the interval [1, positive infinity], find the value range of real number a

As we know, because FX = log 2x (the outer function is an increasing function, so the inner function x ^ 2 ax - 2A increases in [1. Positive infinity]) and because the symmetry axis is - A / 2 and the opening of the inner function is upward, only the symmetry axis is less than or equal to 1, the result is a greater than or equal to - 2

Simple operation: 136 times 271 minus 135 times 271 plus 136

136*271-135/135*271+136
=136*272-1*271
=136*271+136*1-1*271
=135*271+136
=36721

Factorization: x ^ 2-y ^ 2-4x-6y-13

x²-y²-4x-6y-5
=（x²-4x+4）-（y²+6y+9）
=(x-2)²-(y+3)²
=(x-2+y+3)(x-2-y-3)
=(x+y+1)(x-y-5)

If Tan (a + U / 4) = 1 / 2 and - U / 2 < a < 0, then the value of (2sina Λ 2 + sin2a) / sin (a - U / 4) is known

∵ Tan (a + 5 / 4) = 1 / 2
(2Sin ^ 2A + sin2a) / sin (A-wu / 4)
=(2sin^2a+2sinacosa)/(sinacosπ/4-cosasinπ/4)
=2sina(sina+cosa)/.[√2/2(sina-cosa)]
=2√2(sina+cosa)/(sina-cosa)
=2√2（sina/cosa+1)/(sina/cosa-1)
=-2√2(1+tana)/(1-tana)
=-2√2(tanπ/4+tana)/(1-tanπ/4tana)
=-2√2tan(a+π/4)
=-2√2*1/2
=-√2

C programming language: Newton iterative method for finding the root of equation
2*x*x*x-4*x*x+3*x-6=0

Program flow analysis:
① The value x0 = 1.5 is the initial value of iteration;
② The initial value x0 is substituted into the equation to calculate f (x0) and f '(x0) at this time. In the program, the variable f is used to describe the value of the equation, and FD is used to describe the value after the derivation of the equation;
③ Calculation increment d = f / FD;
④ Calculate the next X, x = x0-d;
⑤ Replace the newly generated x with x0 to prepare for the next iteration;
⑥ If the absolute value of D is greater than 1e-3, repeat step 2, 3 and 5
Source code:
#include
main()
{
float x,x0,d,f,fd;
x0=0;
do {
f=2*x0*x0*x0-4*x0*x0+3*x0-6;
fd=6*x0*x0-8*x0+3;
d=f/fd;
x=x0-d;
x0=x;
}while(fabs(d)>1e-3);
printf("x=%f\n",x);
}

Simple operation of 27.5 × 9.9 + 2.75

27.5*9.9+2.75
=27.5*（9.9+0.1）
= 275