Have you noticed the ellipsis in the poem? What other natural languages do you understand? Please write a few sentences according to the sentence pattern of the poem It's the language of nature

Have you noticed the ellipsis in the poem? What other natural languages do you understand? Please write a few sentences according to the sentence pattern of the poem It's the language of nature

I've long forgotten what I learned in primary school

Please imitate the sentence pattern of "fascinating classroom, hot work, fun outing, chasing match", imagine the content of ellipsis, and write some phrases like this

Omit the various scenes of the students together
Red faced debate, passionate speech, chirping talk, heart of tacit understanding... I will never forget this life!

What does the ellipsis in the second paragraph of the text omit? Please continue with one or two sentences
Speed is best today

If you are a doctor, you should cooperate with the nurse to complete the operation successfully. If you are a performer, you should follow the conductor of the musician to complete the beautiful music

In △ ABC, ∠ B = C, e is a point on AC, ed ⊥ BC, DF ⊥ AB, the perpendicular feet are D and f respectively, if ∠ AED = 130 degree,

What do you want? From the topic
∠B=∠C=∠FDE=40°,
Then we get △ CDE ∽ BFD. I hope I can help you solve the problem

View and drawing method of function image
How to look at the first-order function and the inverse proportion function, and how to quickly know the values of several special values? The most important thing is how to look at the image of the second-order function. If you draw it, you can barely draw the value and range of the special values, such as the value of K and B in which part of the image in y = KX + B,

Once K represents the degree of tilt, the larger the positive number is, the steeper the image is, and the steeper the negative absolute value is. B represents the intercept on the Y axis, the positive value is above the X axis, and the negative value is below
The degree of opening and closing is determined by A. the larger the absolute value is, the smaller the opening is. The positive opening of a is upward and the negative value is downward
C is the intercept of Y axis. The axis of symmetry is determined by B and a

On the mathematical problems of vectors,
If AC is a diameter of circle O and angle ABC is the circumference angle, the vector method is used to prove that angle ABC = 90 degrees

Prove: let the radius of circle o be r. let the vector OA = x, the vector ob = y, then the vector OC = - x, and | x | = | y | = R. so AB * BC = (ob - OA) * (oc - OB) = (Y - x) * (- X - y) = x ^ 2 - y ^ 2 = R ^ 2 - R ^ 2 = 0. So ab ⊥ BC. That is, ∠ ABC = 90 °. = = = =

Bisectors of two outer angles of triangle intersect at point P to connect BP, bisector of angle ABC
The bisectors of the two outer angles of a triangle intersect at point P and connect BP. The bisector of angle ABC proves that BP is the bisector of triangle ABC

Make PF ⊥ AC through P and cross AC to F
PE ⊥ BC is made through P and BC extension line is made through E
Make PG ⊥ AB through P and cross AB extension line to g
∵ AP bisector ∠ GAC, ∵ PG = PF (the distance from the point on the bisector to both sides of the angle is equal)
∵ CP bisection ∠ ace
∴PF=PE
｜ PE = PG (equivalent substitution)
∵∠BGP=∠PEB=90
,BP=BP
The triangle BGP is equal to the triangle PBE (HL)
∴∠ABP=∠PBE
The bisector of ABC is BP

The reduction contains an unknown Pythagorean theorem x ^ 2 + 9 = (2x) ^ 2

x^2+9=4x^2
3x^2=9
x^=3,
X = root 3

If the vector a = (2, - 5), the absolute value vector b = the absolute value vector a, and the vector a and the vector B are perpendicular to each other, then the

Let B (m, n)
Absolute value B vector = absolute value a vector
m²+n²=2²+(-5)²=29
A vector and B vector are perpendicular to each other
(2,-5) *（m,n） =0
2m-5n= 0
m=5 n=2
Or M = - 5, n = - 2

As shown in the figure, points D and E are on the edge of triangle ABC, ab = AC, ad = AE

∵ ad = AE (known)
∵∠ ade = ∠ AED (equilateral equal angle)
∵ ∠ADE+∠ADB=180°
∠ AED + ∠ AEC = 180 ° (equality property)
The complement of equal angle is equal
∵ AB = AC (known)
← B = ∠ C (equal angle to equal edge)
In △ abd and △ AED
∠ B = ∠ C (proved)
∠ ADB = ∠ AEC (proven)
AB = AC (known)
∴△ABD∽△AED（A.A.S)
Ψ BD = Ce (the corresponding sides of congruent triangles are equal)